1945. 字符串转化后的各位数字之和

1945. 字符串转化后的各位数字之和

题解:

  • 按题意模拟
  • 先将英文字母转成数字
  • 每转一轮数字,下一轮数字为上一轮数字的每位之和
class Solution {
    public int getLucky(String s, int k) {
        StringBuilder stringBuilder = new StringBuilder();
        for (char c : s.toCharArray()) {
            if (c >= 'a' && c <= 'z') {
                int i = c - 'a' + 1;
                stringBuilder.append(i);
            }
        }
        while (k-- > 0) {
            int temp = 0;
            for (char c : stringBuilder.toString().toCharArray()) {
                temp += c - '0';
            }
            stringBuilder = new StringBuilder(String.valueOf(temp));
        }
        return Integer.parseInt(stringBuilder.toString());
    }
}
posted @ 2022-12-15 20:58  Eiffelzero  阅读(46)  评论(0)    收藏  举报