create function fmerg(@id int)
returns varchar(8000)
as
begin
declare @str varchar(8000)
set @str=''
select @str=@str+','+ short_name from v_person where psn_code=@id
set @str=right(@str,len(@str)-1)
return(@str)
End
go
--调用自定义函数得到结果
select distinct psn_code,dbo.fmerg(psn_code) from v_person

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