利用莱布尼茨公式计算π
from tqdm import trange pi = 0 for i in trange(1000000000): if i%2 == 0: pi += 1/(2*i+1) else: pi -= 1/(2*i+1) pi = pi*4 print(pi)
理论上迭代次数越大,数就越接近π
from tqdm import trange pi = 0 for i in trange(1000000000): if i%2 == 0: pi += 1/(2*i+1) else: pi -= 1/(2*i+1) pi = pi*4 print(pi)
理论上迭代次数越大,数就越接近π