ManyToMany OrderBy

有A、B表和A_B中间表,A_B中间表只有A、B表的id,想让A中的bs以date列排序:

@Entity
@Table(name="A")
public class A implements java.io.Serializable {

    private Set<B> bs = new HashSet<B>(0);

    @ManyToMany(fetch=FetchType.LAZY)
    @JoinTable(name="A_B", joinColumns = { 
        @JoinColumn(name="a_id", nullable=false, updatable=false) }, inverseJoinColumns = { 
        @JoinColumn(name="b_id", nullable=false, updatable=false) })
    @OrderBy(clause = "date desc")
    public Set<B> getBs() {
        return this.bs;
    }
}

@Entity
@Table(name="B")
public class B implements java.io.Serializable {

    @Column(name="date", nullable=false, length=29)
    private Date date;

    /* setters and getters */
}

 

以上代码中的@OrderByorg.hibernate.annotations.OrderBy,如果使用A_B中间表中没有的列进行排序会出错,改成javax.persistence.OrderBy@OrderBy就行了:

@ManyToMany(fetch=FetchType.LAZY)
@JoinTable(name="A_B", joinColumns = { 
    @JoinColumn(name="a_id", nullable=false, updatable=false) }, inverseJoinColumns = { 
    @JoinColumn(name="b_id", nullable=false, updatable=false) })
@javax.persistence.OrderBy(value = "date desc")
public Set<B> getBs() {
    return this.bs;
}

 

org.hibernate.annotations.OrderBy把clause中的列名(date)当作是A_B表的列名,而javax.persistence.OrderBy把value中的列名(date)当作B表列名。

 

另:@OrderBy是在内存中排序,在db中不见得是有序的,@OrderColumn是数据在db中就是有序的

posted @ 2016-08-23 23:11  raindream  阅读(2024)  评论(0编辑  收藏  举报