冒泡排序,斐波拉契迭代、生成器

冒泡排序:

l=[1,3,0,100,1000,8,2,9,5,11,8]

def maopao(l):
    for i in range(len(l)-1):
        if l[i+1] < l[i]:
            a= l[i]
            b=l[i+1]
            l[i] = b
            l[i+1] = a
    return l

for i in range(len(l)):
    maopao(l)
print l
返回:[0, 1, 2, 3, 5, 8, 8, 9, 11, 100, 1000]

 

斐波拉契-生成器(返回小于100的数):

def fbg(max):
    x,y=0,1
    while y < max:
        yield y
        x,y=y,x+y

g=fbg(100)
for i in g:
    print i
返回:
1
1
2
3
5
8
13
21
34
55
89

斐波拉契-迭代1(返回小于100的数):

def fbd(x,y,max):
    print y
    x,y=y,x+y
    if y<max:
        fbd(x,y,max)
fbd(0,1,100)

斐波拉契-迭代2(返回前10个数):

def fbd(n):
    if n==0:
        return 0
    if n==1:
        return 1
    else:
        r=fbd(n-1) + fbd(n-2)
        return r
for i in range(10):
    print fbd(i)
返回:
0
1
1
2
3
5
8
13
21
34

 

posted on 2016-04-29 14:06  momingliu11  阅读(393)  评论(0编辑  收藏  举报