【Agorithm】一次一密加密解密算法
1 #include<iostream> 2 #include<cstdio> 3 #include<cstdlib> 4 #include<ctime> 5 #include<cmath> 6 #include<cstring> 7 #include<string> 8 #include<windows.h> 9 #define MAX 100 10 11 using namespace std; 12 13 char key[MAX]; 14 int len; 15 16 char *bitcode(char *str){ 17 char *wen; 18 if((wen = (char*)malloc(len+1))==NULL){ 19 cout<<"申请内存失败！"<<endl; 20 exit(1); 21 } 22 for(int i=0; i<len; i++){ 23 wen[i] = str[i]^key[i]; 24 } 25 wen[len] = '\0'; 26 return wen; 27 } 28 29 30 int main(){ 31 32 char str[MAX]; 33 char *miwen, *mingwen; 34 char again; 35 36 srand(time(NULL)); 37 cout<<"\t\t\t\t一次一密加密算法演示！\n\n"; 38 s1: 39 cout<<"请输入需要加密的明文字符串："; 40 fflush(stdin); 41 gets(str); 42 len = strlen(str); 43 for(int i=0; i<len; i++){ 44 key[i] = rand()%10+'0'; 45 } 46 cout<<"此次加密的密钥序列为："; 47 for(int i=0; i<len; i++){ 48 cout<<key[i]; 49 } 50 cout<<endl; 51 miwen = bitcode(str); 52 cout<<"加密前的明文为："; 53 cout<<str<<endl; 54 cout<<"加密后的密文为："<<miwen<<endl; 55 mingwen = bitcode(miwen); 56 cout<<"解密后的明文为："<<mingwen<<endl; 57 cout<<endl; 58 59 s2: 60 cout<<"继续执行 （Y/N）？"; 61 fflush(stdin); 62 cin>>again; 63 if(again =='y'|| again =='Y'){ 64 goto s1; 65 } 66 else if(again == 'n' || again == 'N'){ 67 cout<<"演示结束！"<<endl; 68 return 0; 69 } 70 else{ 71 cout<<"输入错误请重新输入！"<<endl; 72 goto s2; 73 } 74 system("pause"); 75 }
以下是运行结果：
