Vector_h

  1 #ifndef  VECTOR_H
  2 #define  VECTOR_H
  3 
  4 #include <algorithm>
  5 
  6 template<typename Object>
  7 class  Vector
  8 {
  9 private:
 10     int theSize;                         //实际数据大小
 11     int theCapacity;                     //实际容器容量大小
 12     Object *objects;                     //基本数组
 13 public:
 14     enum { SPACE_CAPACITY = 16 };        //默认容量大小
 15     
 16     explicit Vector(int initSize = 0)    //单参数构造函数要用explicit()避免类型在后台转换
 17         : theSize(initSize), theCapacity(initSize + SPACE_CAPACITY) {
 18         objects = new Object[theCapacity];
 19     }
 20     Vector(const Vector& rhs) : objects(NULL) {    //复制构造函数--调用operator=对已有的Vector进行复制
 21         operator = (rhs);
 22     }
 23     ~Vector() {
 24         delete[] objects;
 25     }
 26 
 27     const Vector& operator = (const Vector& rhs) //重载赋值运算符
 28     {
 29         if (this != &rhs)                        //避免复制自身--混淆检验
 30         {
 31             delete []objects;                    //删除旧的内存空间
 32             theSize = rhs.size();                //生成同样的样本大小
 33             theCapacity = rhs.theCapacity;       //生成同样的容量大小
 34 
 35             objects = new Object[capacity()];    //生成与所复制的Vector同样容量的新数组
 36             for (int k = 0; k < size(); k++)
 37                 objects[k] = rhs.objects[k]; 
 38         }
 39         return *this;
 40     }
 41     
 42     void resize(int newSize)
 43     {
 44         if (newSize > theCapacity)        //重置大小
 45             reserve(newSize * 2 + 1);     //新大小
 46         theSize = newSize;
 47     }
 48 
 49     //扩容
 50     void reserve(int newCapacity)
 51     {
 52         if (newCapacity < theSize)        //至少和(样本大小)一样大
 53             return;
 54 
 55         Object *oldArray = objects;       //oldArray--用于复制旧数组内容
 56         objects = new Object[newCapacity];
 57         for (int k = 0; k < theSize; k++)
 58             objects[k] = oldArray[k];
 59                     
 60         theCapacity = newCapacity;
 61         delete []oldArray;
 62     }
 63 
 64     Object& operator[] (int index)
 65     {
 66         return objects[index];
 67     }
 68     const Object& operator[] (int index) const
 69     {
 70         return objects[index];
 71     }
 72 
 73     bool empty() const {
 74         return size() == 0;
 75     }
 76     
 77     int size() const {
 78         return theSize;
 79     }
 80     int capacity() const {
 81         return theCapacity;
 82     }
 83     //在数据尾端插入元素
 84     void push_back(const Object& x) {
 85         if (theSize == theCapacity)
 86             reserve(2 * theCapacity + 1);
 87         objects[theSize++] = x;
 88     }
 89 
 90     //在index位置前端插入数据data
 91     void insert(int index, const Object& data) {
 92         if (theSize == theCapacity)
 93             reserve(2 * theCapacity + 1);
 94         for (int i = theSize; i >= index; i--) {
 95             objects[i] = objects[i - 1];
 96         }
 97         objects[index] = data;
 98         theSize++;
 99     }
100 
101     void pop_back() {
102         theSize--;
103     }
104 
105     //区间删除 [lo, hi)  --- 左闭右开!! --- 删除索引从 1,2..k
106     int remove(int lo, int hi) {
107         if (lo == hi) return 0;
108         while (hi < theSize) {
109             objects[lo++] = objects[hi++];      //[hi,theSize)顺次前移 hi-lo 位
110         }
111         theSize = lo;
112         return hi - lo;                         //返回被删除元素数目
113     }
114     //重载删除一个指定位置元素--删除r位置元素,[r,r+1). 如果先写删除单个元素函数,删除区间时会低效.
115     Object remove(int r) {
116         Object oldElem = objects[r];
117         remove(r, r + 1);                   
118         return oldElem;                         //返回删除的元素
119     }
120 
121     //order the vector
122     //二分查找--有序向量
123     int Search(Object &elem, int lo, int hi) {
124         while (lo < hi) {        //不变性: A[0,lo) <= e < A[hi,n)
125             int mid = (lo + hi) >> 1;                 // 以中点为轴
126             (elem < objects[mid]) ? hi = mid : lo = mid + 1; // [lo,mi) 或 (mi,hi)
127         }                                             // 出口时,A[lo = hi]为大于elem的最小元素
128         return --lo;                                  // lo-1即为不大于elem的元素的最大秩
129     }
130 
131     /*mergesort()归并排序
132     /*无序向量的递归分解,两个有序的子序列合成大的子序列*/
133     void mergeSort(int lo, int hi) {
134         if (hi - lo < 2) return;
135         int mid = (lo + hi) >> 1;
136         mergeSort(lo, mid);                           //对前半段排序
137         mergeSort(mid, hi);                           //对后半段排序
138         merge(lo, mid, hi);                            //归并
139     }
140      
141     //归并---O(nlogn), T(n) = 2T(n/2) + O(n)
142     void merge(int lo, int mid, int hi) {
143         //A用来存放合并后的向量,B,C进行比较(前后子向量比较)
144         Object *A = objects + lo;          //合并后的向量A[0,hi-lo) = objects[lo,hi)
145         int lb = mid - lo;
146         Object *B = new Object[lb];        //前子向量 B[0,lb) = objects[lo,mi)
147         for (int i = 0; i < lb; B[i] = A[i++]);   //复制前子向量
148         int lc = hi - mid;
149         Object *C = objects + mid;         //后子向量
150         for (int i = 0, j = 0, k = 0; (j < lb || k < lc);) {
151             //B[i], C[k]中小者转至A的末尾.        
152             //因为C本来就占据A中,不需要考虑提前耗尽情况
153             if ((j < lb) && (k >= lc || C[k] >= B[j]))      //C[k]已无或不小
154                 A[i++] = B[j++];
155             if ((k < lc) && (j >= lb || B[j] >= C[k]))      //B[k]已无或不小
156                 A[i++] = C[k++];
157         }
158         delete []B;
159     }
160 
161     //有序向量的去重, 重复的元素必定紧邻,每个区间只保留单个---每次常数,累计O(n)
162     int uniquify() {
163         int i = 0, j = 0;            //各对互异,"相邻"元素的秩,逐一扫描,直至末元素
164         while (++j < theSize) {
165             //跳过雷同者,发现不同元素时,向前移至紧邻元素
166             if (objects[i] != objects[j]) objects[++i] = objects[j];
167         }
168         theSize = ++i; 
169         return j - i;                //返回被删除元素总数
170     }
171 
172 
173     //得到尾元素
174     const Object& back() const {
175         return objects[theSize - 1];
176     }
177     
178     typedef Object * iterator;
179     typedef const Object * const_iterator;
180 
181     iterator begin() {
182         return &objects[0];
183     }
184     const_iterator begin() const {
185         return &objects[0];
186     }
187     iterator end() {               //尾后的不存在的指针
188         return &objects[size()];     
189     }
190     const_iterator end() const {
191         return &objects[size()];
192     }
193 
194 };
195 
196 
197 
198 #endif // VECTOR_H
  1 /************************************************************************/
  2 /* Vs2013, c++11标准编写      测试vector.h                                */
  3 /************************************************************************/
  4 #include <iostream>
  5 #include <cstring>
  6 #include "Vector.h"
  7 using namespace std;
  8 
  9 int test[100] = { 0 };
 10 
 11 void Merge(int *test, int lo, int mid, int hi);
 12 void MergeSort(int *test, int lo, int hi) {
 13     if (hi - lo < 2) return;
 14     int mid = (lo + hi) >> 1;
 15     MergeSort(test, lo, mid);                           //对前半段排序
 16     MergeSort(test, mid, hi);                           //对后半段排序
 17     Merge(test, lo, mid, hi);                            //归并
 18 }
 19 
 20 //归并---O(nlogn), T(n) = 2T(n/2) + O(n)
 21 void Merge(int *test, int lo, int mid, int hi) {
 22     //A用来存放合并后的向量,B,C进行比较(前后子向量比较)
 23     int  *A = test + lo;          //合并后的向量A[0,hi-lo) = int s[lo,hi)
 24     int lb = mid - lo;
 25     int  *B = new int [lb];        //前子向量 B[0,lb) = int s[lo,mi)
 26     for (int i = 0; i < lb; B[i] = A[i++]);   //复制前子向量
 27     int lc = hi - mid;
 28     int  *C = test + mid;         //后子向量
 29     for (int i = 0, j = 0, k = 0; (j < lb || k < lc);) {
 30         //B[i], C[k]中小者转至A的末尾.        
 31         //因为C本来就占据A中,不需要考虑提前耗尽情况
 32         if ((j < lb) && (k >= lc || C[k] >= B[j]))      //C[k]已无或不小
 33             A[i++] = B[j++];
 34         if ((k < lc) && (j >= lb || B[j] >= C[k]))      //B[k]已无或不小
 35             A[i++] = C[k++];
 36     }
 37     delete[]B;
 38 }
 39 
 40 
 41 int main()
 42 {
 43     //用来测试 非模板写的 归并排序 算法
 44     /*int Test[13] = { 1, 5, 2, 3, 6, 8, 9, 10, 13, 12, 4, 7, 11 };
 45     MergeSort(Test, 0, 13);
 46     for (int i = 0; i < 13; i++)
 47     cout << Test[i] << " ";
 48     cout << endl;*/
 49 
 50     Vector<int> testOne;
 51     int testData, cnt, index;
 52     cout << "输入数字数目: ";
 53     cin >> cnt;
 54     cout << "输入 " << cnt << "个数: ";
 55     while (cnt-- && cin >> testData)
 56     {
 57         testOne.push_back(testData);
 58     }
 59 
 60     cout << "显示所有元素: ";
 61     for (int i = 0; i < testOne.size(); i++) {
 62         cout << testOne[i] << " ";
 63     }
 64     cout << endl;
 65     
 66     cout << "\n输入插入元素位置(0...k)和插入的数值: ";
 67     cin >> index >> testData;
 68     testOne.insert(index, testData);
 69     cout << "显示所有元素: ";
 70     for (int i = 0; i < testOne.size(); i++) {
 71         cout << testOne[i] << " ";
 72     }
 73     cout << endl;
 74 
 75     cout << "\n输入删除元素位置(0...k): ";
 76     cin >> index;
 77     testOne.remove(index);
 78     cout << "显示所有元素: ";
 79     for (int i = 0; i < testOne.size(); i++) {
 80         cout << testOne[i] << " ";
 81     }
 82     cout << endl;
 83     
 84     cout << "\n归并排序向量元素: \n"; testOne.mergeSort(0, testOne.size());
 85     cout << "显示所有元素: ";
 86     for (int i = 0; i < testOne.size(); i++) {
 87         cout << testOne[i] << " ";
 88     }
 89     cout << endl;
 90 
 91     cout << "\n(有序向量)(二分查找:)输入查找元素: ";
 92     cin >> testData;
 93     cout << "查找位置返回(不大于查找元素的最大的秩): "
 94         << testOne.Search(testData, 0, testOne.size()) << endl;
 95 
 96     cout << "\n(有序向量)去除重复元素: \n"; testOne.uniquify();
 97     cout << "显示所有元素: ";
 98     for (int i = 0; i < testOne.size(); i++) {
 99         cout << testOne[i] << " ";
100     }
101     cout << endl;
102 
103     return 0;
104 
105 }

 

posted @ 2016-09-22 22:18  douzujun  阅读(799)  评论(2编辑  收藏  举报