选择排序

思路:

连续找到区间范围内最小值,然后排入到指定位置

时间复杂度为O(n^2)

代码

import java.util.Arrays;

public class Client {

    private static void selectSort(int[] arr){
        for (int i = 0; i < arr.length; i++) {
            int lowestIndex = i;
            for (int j = i + 1; j < arr.length; j++) {
                if(arr[j] < arr[lowestIndex]){
                    lowestIndex = j;
                }
            }
            if(lowestIndex != i){
                int temp = arr[i];
                arr[i] = arr[lowestIndex];
                arr[lowestIndex] = temp;
            }
        }
    }


    public static void main(String[] args)  {

        int[] arr= {4,5,55,3,22,4,6,7,43,7,89,0};
        selectSort(arr);
        System.out.println(Arrays.toString(arr));

    }
}

 

posted @ 2020-12-18 22:30  冬马党  阅读(63)  评论(0)    收藏  举报