实验六

task4

#include <stdio.h>
#define N 10
typedef struct {
char isbn[20];
char name[80];
char author[80];
double sales_price;
int sales_count;
} Book;
void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);
int main() {
Book x[N] = {
{"978-7-5327-6882-4", "门廊之外", "罗纳德·比", 42, 51},
{"978-7-308-12047-5", "自由与爱之路：人权色列史", "以赛亚·伯林", 49, 30},
{"978-7-5596-4725-6", "无的开始：世界进步的本源", "项飙", 58, 59},
{"978-7-5447-5464-8", "软件体的生命周期", "特德·姜", 33, 80},
{"978-7-5212-0975-6", "芯片简史", "汪波", 74.9, 49},
{"978-7-5133-5150-8", "鱼", "布兰登·桑德森", 88, 65},
{"978-7-5217-7119-0", "天方夜谭历险记：世界进步的本源", "云也退", 42, 45},
{"978-7-5133-5109-6", "你好外星人", "河森正治堀田繚", 118, 44},
{"978-7-111-05098-9", "天的开始：世界进步的本源", "威廉·萨默塞", 37.5, 55},
{"978-7-229-14156-1", "源泉", "安·兰德", 84, 59}
};
printf("图书销量排名(按销售册数): \n");
sort(x, N);
output(x, N);
printf("\n图书销售总额：%.2f\n", sales_amount(x, N));
return 0;
}
void output(Book x[], int n) {
printf("%-15s%-30s%-20s%-10s%s\n", "ISBN", "书名", "作者", "售价", "销售册数");
for (int i = 0; i < n; i++) {
printf("%-15s%-30s%-20s%-10.1f%d\n",
x[i].isbn, x[i].name, x[i].author,
x[i].sales_price, x[i].sales_count);
}
}
void sort(Book x[], int n) {
for (int i = 0; i < n - 1; i++) {
for (int j = 0; j < n - 1 - i; j++) {
if (x[j].sales_count < x[j + 1].sales_count) {
Book temp = x[j];
x[j] = x[j + 1];
x[j + 1] = temp;
}
}
}
}
double sales_amount(Book x[], int n) {
double sum = 0;
for (int i = 0; i < n; i++) {
sum += x[i].sales_price * x[i].sales_count;
}
return sum;
}

 task5

#include <stdio.h>
typedef struct {
int year;
int month;
int day;
} Date;
void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);
void test1() {
Date d;
int i;
printf("输入日期:(以形如2025-12-14这样的形式输入)\n");
for (i = 0; i < 3; ++i) {
input(&d);
printf("%d-%02d-%02d是这一年中第%d天\n", d.year, d.month, d.day, day_of_year(d));
}
}
void test2() {
Date Alice_birth, Bob_birth;
int ans;
int i;
printf("输入Alice和Bob的生日:(以形如2025-12-14这样的形式输入)\n");
for (i = 0; i < 3; ++i) {
input(&Alice_birth);
input(&Bob_birth);
ans = compare_dates(Alice_birth, Bob_birth);
if (ans == 0)
printf("Alice和Bob一样大\n");
else if (ans < 0)
printf("Alice大\n");
else
printf("Alice小\n");
}
}
int main() {
printf("===测试1: 输入日期, 打印输出这是一年中第多少天===\n");
test1();
printf("\n===测试2: 两个人年龄大小关系===\n");
test2();
return 0;
}
void input(Date *pd) {
scanf("%d-%d-%d", &pd->year, &pd->month, &pd->day);
}
int day_of_year(Date d) {
int i;
int days = 0;
int month_days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

if ((d.year % 4 == 0 && d.year % 100 != 0) || (d.year % 400 == 0)) {
month_days[1] = 29;
}

for (i = 0; i < d.month - 1; i++) {
days += month_days[i];
}
days += d.day;

return days;
}
int compare_dates(Date d1, Date d2) {
if (d1.year > d2.year) return 1;
if (d1.year < d2.year) return -1;
if (d1.month > d2.month) return 1;
if (d1.month < d2.month) return -1;
if (d1.day > d2.day) return 1;
if (d1.day < d2.day) return -1;
return 0;
}

 task6

#include <stdio.h>
#include <string.h>
enum Role {admin, student, teacher};
typedef struct {
char username[20];
char password[20];
enum Role role;
} Account;
void output(Account x[], int n);
int main() {
Account a[] = {
{"A1001", "123456f", student},
{"A1002", "a123dddf", student},
{"A1009", "xyg123111", admin},
{"T1111", "123dfe34", teacher},
{"A1005", "xdFngJq17", student}
};
int n;
n = sizeof(a) / sizeof(Account);
output(a, n);
return 0;
}
void output(Account x[], int n) {
int i, j;
printf("%-15s%-15s%-15s\n", "用户名", "密码", "账户类型");

for (i = 0; i < n; i++) {
printf("%-15s", x[i].username);
for (j = 0; x[i].password[j] != '\0'; j++) {
printf("*");
}
for (; j < 15; j++) {
printf(" ");
}

if (x[i].role == admin) {
printf("admin\n");
} else if (x[i].role == student) {
printf("student\n");
} else {
printf("teacher\n");
}
}
}

 task7

#include <stdio.h>
#include <string.h>

typedef struct {
char name[20];
char phone[12];
int vip;
} Contact;
void set_vip(Contact t[], int n, char name[]);
void display(Contact t[], int n);
void output(Contact x[], int n);
int search_vip(Contact x[], int n, char name[]);
#define N 10
int main() {
Contact list[N] = {{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18620010394", 0},
{"李四", "13005151867", 0},
{"王五", "18882533927", 0},
{"赵六", "15336671904", 0},
{"周七", "13682882232", 0},
{"孙八", "13751132575", 0},
{"吴九", "18077774097", 0},
{"郑十", "18630756169", 0}};
int vip_cnt, i;
char name[20];
printf("显示初始通讯录信息:\n");
output(list, N);
printf("输入需要设置的紧急联系人个数: ");
scanf("%d", &vip_cnt);
printf("输入%d个紧急联系人姓名:\n", vip_cnt);
for (i = 0; i < vip_cnt; i++) {
scanf("%s", name);
set_vip(list, N, name);
}

printf("正确显示通讯录列表:(按姓名升序排序并显示,紧急联系人最先显示)\n");
display(list, N);
return 0;
}
void set_vip(Contact t[], int n, char name[]) {
int i;
for (i = 0; i < n; i++) {
if (strcmp(t[i].name, name) == 0) {
t[i].vip = 1;
return;
}
}
}

void display(Contact t[], int n) {
int i, j;
Contact temp;

for (i = 0; i < n - 1; i++) {
for (j = 0; j < n - 1 - i; j++) {
if (strcmp(t[j].name, t[j + 1].name) > 0) {
temp = t[j];
t[j] = t[j + 1];
t[j + 1] = temp;
}
}
}

printf("【紧急联系人】\n");
for (i = 0; i < n; i++) {
if (t[i].vip == 1) {
printf("%s %s\n", t[i].name, t[i].phone);
}
}
printf("【普通联系人】\n");
for (i = 0; i < n; i++) {
if (t[i].vip == 0) {
printf("%s %s\n", t[i].name, t[i].phone);
}
}
}

void output(Contact x[], int n) {
int i;
for (i = 0; i < n; i++) {
printf("%s %s", x[i].name, x[i].phone);
if (i < n - 1) {
printf("，");
}
}
printf("\n");
}

int search_vip(Contact x[], int n, char name[]) {
int i;
for (i = 0; i < n; i++) {
if (strcmp(x[i].name, name) == 0 && x[i].vip == 1) {
return 1;
}
}
return 0;
}