文章分类 - RMQ
摘要:使用nlogn的时间和空间进行预处理,A[i][j]储存的为从i开始的2^j个元素中的最值。代码未经编译,仅供参考class ST { public: ST(vector vals) : vals_(vals) { maxes_.resize(vals.size()); mines_.resize(vals.size()); } void Init() { int size = vals_.size(); for (int i = 0; i = size) break; int max = 0; int min = 0; ...
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摘要:线段树保存当前节点的最大(小)值,未经编译,仅供参考#define MAX 0xfffffff#define MIN -0xfffffffstruct Node { Node():left_(NULL), right_(NULL), head_(0), tail_(0), min_(0), max_(0) {} Node* left_; Node* right_; int head_; int tail_; int min_; int max_;};class SegmentTree { public: SegmentTree(vector values) : root_(NU...
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