实验6

实验任务1

程序源码

#include <stdio.h>
#include <string.h> 
#define N 3 

typedef struct student {
    int id;
    char name[20];
    char subject[20];
    double perf;
    double mid;
    double final;
    double total;
    char level[10];
} STU;

void input(STU [], int); 
void output(STU [], int);
void calc(STU [], int);
int fail(STU [], STU [], int);
void sort(STU [], int);

int main() {
    STU st[N], fst[N];
    int k;
    
    printf("录入学生成绩信息:\n");
    input(st, N);
    
    printf("\n成绩处理...\n");
    calc(st, N);
    
    k = fail(st, fst, N);
    sort(st, N);
    printf("\n学生成绩排名情况:\n");
    output(st, N);
    
    printf("\n不及格学生信息:\n");
    output(fst, k);
    
    return 0;
} 

void input(STU s[], int n) {
    int i;
    
    for(i = 0; i < n; i++)
        scanf("%d %s %s %lf %lf %lf", &s[i].id, s[i].name, s[i].subject,
                                      &s[i].perf, &s[i].mid, &s[i].final);
}

void output(STU s[], int n) {
       int i;
   
      printf("-----------------\n");
      printf("学号   姓名     科目   平时   期中   期末   总评   等级\n");
       for(i = 0; i<n; i++)
          printf("%d   %-6s   %-4s   %-4.0f   %-4.0f   %-4.0f   %-4.1f   %s\n",s[i].id,s[i].name,s[i].subject,s[i].perf,s[i].mid,s[i].final,s[i].total,s[i].level);
}


void calc(STU s[],int n) {
    int i;

    for(i = 0; i < n; i++) {    
        s[i].total = s[i].perf * 0.2 + 
                     s[i].mid * 0.2 +
                     s[i].final * 0.6;
        
        if(s[i].total >= 90)
          strcpy(s[i].level, "");
        else if(s[i].total >= 80 && s[i].total < 90)
          strcpy(s[i].level, "");
        else if(s[i].total >= 70 && s[i].total < 80)
          strcpy(s[i].level, ""); 
        else if(s[i].total >= 60 && s[i].total < 70)
          strcpy(s[i].level, "及格");
        else
          strcpy(s[i].level, "不及格");         
    }
}

int fail(STU s[], STU t[], int n) {
      int i, k = 0;
      
      for(i = 0; i < n; i++)
          if(s[i].total < 60)
            t[k++] = s[i];
            
    return k;
}

void sort(STU s[], int n) {
    int i, j;
    STU t;
    
    for(i = 0; i < n-1; i++)
      for(j = 0; j < n-1-i; j++)
        if(s[j].total < s[j+1].total) {
            t = s[j];
            s[j] = s[j+1];
            s[j+1] = t;
        }
}

 

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实验任务2

程序源码

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define N 10
#define M 80

typedef struct{
    char name[M];
    char author[M];
}Book;

int main(){
    Book x[N] = { {"一九八四》", "乔治.奥威尔"},
                  {"《美丽新世界》", "赫胥黎"},
                  {"《昨日的世界》", "斯蒂芬.茨威格"}, 
                  {"《万历十五年》", "黄仁宇"},
                  {"《一只特立独行的猪》", "王小波"},
                  {"《百年孤独》", "马尔克斯"},
                  {"《查令十字街84号》", "海莲.汉芙"},
                  {"《只是孩子》", "帕蒂.史密斯"}, 
                  {"《刀锋》", "毛姆"},
                  {"《沉默的大多数》", "王小波"} };
    Book *ptr;
    int i;
    char author[M];

    printf("所有图书信息:\n");
    for(ptr = x; ptr < x + N; ++ptr)
        printf("%-30s%-30s\n", ptr->name, ptr->author);

    printf("\n输入作者名:");
    gets(author);
    for(ptr = x; ptr < x + N; ++ptr)
        if(strcmp(ptr->author, author) == 0){
            printf("%-30s%-30s\n", ptr->name, ptr->author);
        }
    system("pause");
    return 0;
}

 

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实验任务3

程序源码

#include<stdio.h>
#include<stdlib.h>
#define N 80

typedef struct Filminfo {
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct Filminfo *next;
}Film;


void output(Film *head);
Film *insert(Film *head, int n);

int main(){
    int n;
    Film *head;

    head = NULL;
    printf("输入影片数目:");
    scanf("%d", &n);

    head = insert(head ,n);

    printf("\n所有影片信息如下:\n");
    output(head);

    system("pause");
    return 0;
}

Film *insert(Film *head, int n){
    int i;
    Film *p;

    for(i = 1; i <= n; ++i){
        p = (Film *)malloc(sizeof(Film));
        printf("请输入第%d部影片信息:", i);
        scanf("%s %s %s %d", p->name, p->director, p->region,&p->year);

        p->next = head;
        head = p;
    }

    return head;
}

void output(Film *head){
    Film *p;

    p = head;
    while(p != NULL){
        printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p->year);
        p = p -> next;
    }
}

 

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实验任务4

程序源码

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define N 100

typedef struct {
    char num[10];
    int s1;
    int s2;
    double sum;
    char level[10];
}STU;

int fun (STU a[], int n, STU h[]);

int main(){
    STU s[N]={ {"GA05", 85, 76},
               {"GA03", 76, 90},
               {"GA02", 69, 90},
               {"GA04", 85, 56},
               {"GA01", 91, 95},
               {"GA07", 72, 80},
               {"GA08", 64, 45},
               {"GA06", 87, 98},
               {"GA015", 85, 86},
               {"GA013", 91, 97} };
    STU h[N];
    int i, k, n = 10;

    k = fun(s, n, h);

    printf("There are :\n");
    for(i = 0; i < k; i++)
        printf("%s %d %d %.2f %s\n", h[i].num, h[i].s1, h[i].s2, h[i].sum, h[i].level);

    system("pause");
    return 0;
}

int fun(STU a[], int n, STU h[]){
    int i,s = 0, j = 0;
    double average;
    
    for(i = 0;i<n;i++)
        {
        a[i].sum = 0.7*a[i].s1 + 0.3*a[i].s2;
        s += a[i].sum;
        }
    average = s/n;
    
    for(i = 0; i<n;i++)
        if(a[i].sum>average){
            h[j] = a[i];
            strcpy(h[j].level,"均分以上");
            j++;
        }
    return j;

}

 

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实验任务5

程序源码

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define N 5

typedef struct {
    char name[10];
    int num;
    int maths;
    int computer;
    int english;
    int sum;
    char level[10];
}STU;

void fun (STU a[], int n);

int main(){
    STU s[6*N]={ {"A001", 1, 34, 67, 80},
               {"B003", 3, 78, 87, 90},
               {"A002", 2, 90, 98, 99},
               {"B002", 4, 56, 78, 98},
               {"A005", 5, 35, 67, 79} };
    int i;

    fun(s, N);
    for(i = 0; i < N; i++)
        printf("%s %d %d %d %d %d %s\n", s[i].name, s[i].num, s[i].maths, s[i].computer, s[i].english, s[i].sum, s[i].level);

    system("pause");
    return 0;
}

void fun(STU a[], int n, STU h[]){
    int i,j = 2000,k = 0;
   for(i = 0; i < n; i++)
       {
       a[i].sum = a[i].maths + a[i].english + a[i].computer;
       }
    for(i = 0; i < n; i++)
       {
       if(k < a[i].sum)
          k = a[i].sum;}
    for(i = 0; i < n; i++)  
        {
        if(j > a[i].sum)
          j = a[i].sum;
        }
    for(i = 0; i<n;i++)
        {
            if(a[i].sum == k )
               {
                   strcpy(a[i].level,"优秀"); 
               }
            else if(a[i].sum == j)
                {
                strcpy(a[i].level,"不及格"); 
            }
            else 
                strcpy(a[i].level,"合格") ;
        }
       
    }

 

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实验任务6

程序源码

#include <stdio.h>
#include<stdlib.h>
#define N 5

typedef struct student {
    long no;
    char name[20];
    int score;
} STU;

void input(STU s[], int n);
int find_min_list(STU s[], STU t[], int n);
void output(STU s[], int n);

int main() {
    STU stu[N], min_list[N];
    int count;

    printf("录入%d个学生信息\n", N);
    input(stu, N);

    printf("\n统计最低分人数和学生信息...\n");
    count = find_min_list(stu, min_list, N);

    printf("\n一共有%d个最低分,信息如下:\n", count);
    output(min_list, count);

    system("pause");
    return 0;
}

void input(STU s[], int n) {
   int i;
   for(i = 0; i< n;i++)
       scanf("%d %s %d",&s[i].no,&s[i].name, &s[i].score);
}

void output(STU s[], int n) {
    int i;
    
    for(i = 0;i < n; i++) 
        printf("%ld %s %d\n", s[i].no, s[i].name, s[i].score);
}

int find_min_list(STU s[], STU t[], int n) {
    int i, m = 0, Min = 1e9;
    
    for(i = 0;i < n; i++)
        if(s[i].score < Min) Min = s[i].score;
        
    for(i = 0;i < n; i++)
        if(s[i].score == Min) t[m ++] = s[i];
    
    return m;

}

 

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posted @ 2023-05-28 15:36  TE-AMO  阅读(5)  评论(0编辑  收藏  举报