实验四
实验任务1
程序源码
#include<stdio.h> #include<stdlib.h> #define N 4 int main(){ int a[N] = {2, 0, 2, 3}; char b[N] = {'2', '0', '2', '3'}; int i; printf("sizeof(int) = %d\n:", sizeof(int)); printf("sizeof(char) = %d\n", sizeof(char)); printf("\n"); for(i = 0; i < N; ++i) printf("%p:%c\n", &b[i], b[i]); printf("\n"); printf("a = %p\n", a); printf("b = %p\n", b); system("pause"); return 0; }
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讨论:
int型数组a是连续存放的,每个元素占用4个字节
char型数组b是连续存放的,每个元素占用1个字节
数组名a对应的值和&a[0]一样,数组名b对应的值和&b[0]一样
程序源码
#include<stdio.h> #include<stdlib.h> #define N 2 #define M 3 int main(){ int a[N][M] = {{1, 2, 3}, {4, 5, 6}}; char b[N][M] = {{'1', '2', '3'}, {'4', '5', '6'}}; int i, j; for(i = 0; i < N; ++i) for(j = 0; j < M; ++j) printf("%p:%d\n", &a[i][j], a[i][j]); printf("\n"); printf("a = %p\n", a); printf("a[0] = %p\n", a[0]); printf("a[1] = %p\n", a[1]); printf("\n"); for(i = 0; i < N; ++i) for(j = 0; j < M; ++j) printf("%p:%c\n", &b[i][j], b[i][j]); printf("\n"); printf("b = %p\n", b); printf("b[0] = %p\n", b[0]); printf("b[1] = %p\n", b[1]); printf("\n"); system("pause"); return 0; }
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讨论:
数组a,在内存中是“按行连续存放的‘’,每个元素占4个字节单元
一样
数组b,在内存中是“按行连续存放的‘’,每个元素占1个字节单元
一样
a[0]和a[1]差12个字节,b[0]和b[1]差3个字节
实验任务2
程序源码
#include<stdio.h> #include<stdlib.h> #include<string.h> #define N 80 void swap_str(char s1[N], char s2[N]); void test1(); void test2(); int main(){ printf("测试1:用两个一维数组,实现两个字符串交换\n"); test1(); printf("\n测试:用二维数组,实现两个字符串交换\n"); test2(); system("pause"); return 0; } void test1(){ char views1[N] = "hey, C, I hate u."; char views2[N] = "hey, C, I love u."; printf("交换前:\n"); puts(views1); puts(views2); swap_str(views1, views2); printf("交换后:\n"); puts(views1); puts(views2); } void test2(){ char views[2][N] = {"hey, C, I hate u.", "hey, C, I, love u."}; printf("交换前:\n"); puts(views[0]); puts(views[1]); swap_str(views[0], views[1]); printf("交换后:\n"); puts(views[0]); puts(views[1]); } void swap_str(char s1[N], char s2[N]){ char tmp[N]; strcpy(tmp, s1); strcpy(s1, s2); strcpy(s2, tmp); }
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讨论
实验任务3
程序源码
#include<stdio.h> #include<stdlib.h> #define N 80 int count(char x[]); int main(){ char words[N+1]; int n; while(gets(words) != NULL){ n = count(words); printf("单词数:%d\n\n", n); } system("pause"); return 0; } int count(char x[]){ int i; int word_flag = 0; int number = 0; for(i= 0; x[i] != '\0'; i++){ if(x[i] == ' ') word_flag = 0; else if(word_flag == 0){ word_flag = 1; number++; } } return number; }
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程序源码
#include<stdio.h> #include<stdlib.h> #define N 1000 int main(){ char line[N]; int word_len; int max_len; int end; int i; while(gets(line) != NULL){ word_len = 0; max_len = 0; end = 0; i =0; while(1){ while(line[i] == ' '){ word_len = 0; i++; } while(line[i] != '\0' && line[i] != ' '){ word_len++; i++; } if(max_len < word_len){ max_len = word_len; end = i; } if(line[i] == '\0') break; } printf("最长单词:"); for(i = end - max_len; i < end; ++i) printf("%c", line[i]); printf("\n\n"); } system("pause"); return 0; }
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实验任务4
程序源码
#include<stdio.h> #include<stdlib.h> #define N 5 void input(int x[], int n); void output(int x[], int n); double average(int x[], int n); void bubble_sort(int x[], int n); int main(){ int scores[N]; double ave; printf("录入%d个分数:\n", N); input(scores, N); printf("\n输出课程分数:\n", N); output(scores, N); printf("\n课程分数处理:计算均分,排序...\n"); ave = average(scores, N); bubble_sort(scores, N); printf("\n输出课程平均分:%.2f\n", ave); printf("\n输出课程分数(高->低):\n"); output(scores, N); system("pause"); return 0; } void input(int x[], int n){ int i; for(i = 0; i < n; ++i) scanf("%d", &x[i]); } void output(int x[], int n){ int i; for(i = 0; i < n; ++i) printf("%d ", x[i]); printf("\n"); } double average(int x[], int n){ int i; double s = 0; for(i = 0; i < n; ++i) s = s + x[i]; return s / n; } void bubble_sort(int x[], int n){ int i, j, t; for(i = 0; i < n-1; ++i) for(j = 0; j < n-i-1; ++j) if(x[j] > x[j+1]){ t = x[j]; x[j] = x[j+1]; x[j+1] = t; } }
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实验任务5
程序源码
#include<stdio.h> #include<stdlib.h> #define N 100 void dec2n(int x, int n); int main(){ int x; printf("输入一个十进制整数:"); while(scanf("%d", &x) != EOF){ dec2n(x, 2); dec2n(x, 8); dec2n(x, 16); printf("\n输入一个十进制整数:"); } system("pause"); return 0; } void dec2n(int x, int n){ char num[N]; char str[N]="0123456789ABCDEF"; int i=0,j,t; while(x!=0){ t=x%n; x=x/n; num[i]=str[t]; i++; } j=i; for(i=j-1;i>=0;i--) printf("%c",num[i]); printf("\n"); }
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实验任务6
程序源码
#include <stdio.h> #include<stdlib.h> #define N 100 #define M 4 void output(int x[][N], int n); void rotate_to_right(int x[][N], int n); int main() { int t[][N] = {{21, 12, 13, 24}, {25, 16, 47, 38}, {29, 11, 32, 54}, {42, 21, 33, 10}}; printf("原始矩阵:\n"); output(t, M); rotate_to_right(t, M); printf("变换后矩阵:\n"); output(t, M); system("pause"); return 0; } void output(int x[][N], int n) { int i, j; for (i = 0; i < n; ++i) { for (j = 0; j < n; ++j) printf("%4d", x[i][j]); printf("\n"); } } void rotate_to_right(int x[][N], int n){ int i,j,t; for(i=0;i<n;i++){ t=x[i][n-1]; for(j=n-1;j>0;j--){ x[i][j]=x[i][j-1]; } x[i][0]=t; } }
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实验任务7
程序源码
#include <stdio.h> #include<stdlib.h> #define N 80 void replace(char x[], char old_char, char new_char); int main() { char text[N] = "Rose will bloom all the time."; printf("原始文本: \n"); printf("%s\n", text); replace(text, 'l', '#'); printf("处理后文本: \n"); printf("%s\n", text); system("pause"); return 0; } void replace(char x[], char old_char, char new_char) { int i; for (i = 0; x[i] != '\0'; ++i) if (x[i] == old_char) x[i] = new_char; }
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程序源码
#include <stdio.h> #include<stdlib.h> #define N 80 int main() { char str[N], ch; int i; printf("输入字符串: "); gets(str); printf("输入一个字符: "); ch = getchar(); printf("截断处理......"); i = 0; while (str[i] != '\0') { if (str[i] == ch){ str[i+1]='\0'; break;} i++; } str[i] ='\0' ; printf("\n截断处理后字符串: %s\n", str); system("pause"); return 0; }
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讨论:replace()的功能:用新的字符替换旧的字符
'\0'是空字符,也是字符串的终止字符
实验任务8
程序源码
#include <stdio.h> #include<stdlib.h> #include <string.h> #define N 5 #define M 20 void bubble_sort(char str[][M], int n); // 函数声明 int main() { char name[][M] = {"Bob", "Bill", "Joseph", "Taylor", "George"}; int i; printf("输出初始名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); printf("\n排序中...\n"); bubble_sort(name, N); printf("\n按字典序输出名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); system("pause"); return 0; } void bubble_sort(char str[][M], int n){ int i,j; char k[M]; for(i=0;i<5;i++) for(j=0;j<n-i-1;j++) if(strcmp(str[j],str[j+1])>0){ strcpy(k,str[j]); strcpy(str[j],str[j+1]); strcpy(str[j+1],k); } }
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