FLOYD

 1 #include <iostream>
 2 #include <iomanip>
 3 
 4 using namespace std;
 5 
 6 int m, n;
 7 int e[10010][10010], t1, t2, t3;
 8 
 9 int main(){
10     cin >> n >> m;
11     for(int i = 1; i <= n; i ++)
12         for(int j = 1; j <= n; j ++)
13             if(i == j) e[i][j] = 0;
14             else e[i][j] = 99999999;
15     for(int i = 1; i <= m; i ++){
16         cin >> t1 >> t2 >> t3;
17         e[t1][t2] = t3;
18     }
19     for(int k = 1; k <= n; k ++)
20         for(int i = 1; i <= n; i ++)
21             for(int j = 1; j <= n; j ++)
22                 if(e[i][j] > e[i][k] + e[k][j]) 
23                     e[i][j] = e[i][k] + e[k][j];
24     for(int i = 1; i <= n; i ++){
25         for(int j = 1; j <= n; j ++) 
26             cout << setw(4) << e[i][j];
27         cout << endl;
28     }
29     return 0;
30 }

posted @ 2017-09-20 17:52 一个天才阅读(144) 评论(0) 收藏举报

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