C# 中将枚举转为为列表项

1. 将一个枚举的成员转换为一个List 

using System;
using System.Linq;
using System.Collections.Generic;
 
public class Example
{
    public enum Days
    {
        Monday = 1,
        Tuesday = 2,
        Wednesday = 3,
        Thursday = 4,
        Friday = 5,
        Saturday = 6,
        Sunday = 7
    }
 
    public static void Main()
    {
        List<Days> days = Enum.GetValues(typeof(Days))
                            .Cast<Days>()
                            .ToList();
 
        Console.WriteLine(String.Join(Environment.NewLine, days));
    }
}
 
/*
    Output:
 
    Monday
    Tuesday
    Wednesday
    Thursday
    Friday
    Saturday
    Sunday
*/

2. 将一个枚举的成员转换为一个数组 Array[ ] 

using System;
 
public class Example
{
    public enum Days
    {
        Monday = 1,
        Tuesday = 2,
        Wednesday = 3,
        Thursday = 4,
        Friday = 5,
        Saturday = 6,
        Sunday = 7
    }
 
    public static void Main()
    {
        Days[] days = (Days[])Enum.GetValues(typeof(Days));
        Console.WriteLine(String.Join(Environment.NewLine, days));
    }
}
 
/*
    Output:
 
    Monday
    Tuesday
    Wednesday
    Thursday
    Friday
    Saturday
    Sunday
*/

3. 将枚举项项带数字值转换为一个List.

using System;
using System.Linq;
using System.Collections.Generic;
 
public class Example
{
    public enum Days
    {
        Monday = 1,
        Tuesday = 2,
        Wednesday = 3,
        Thursday = 4,
        Friday = 5,
        Saturday = 6,
        Sunday = 7
    }
 
    public static void Main()
    {
        var days = Enum.GetValues(typeof(Days))
                        .Cast<Days>()
                        .Select(d => (d, (int)d))
                        .ToList();
 
        Console.WriteLine(String.Join(Environment.NewLine, days));
    }
}
 
/*
    Output:
 
    (Monday, 1)
    (Tuesday, 2)
    (Wednesday, 3)
    (Thursday, 4)
    (Friday, 5)
    (Saturday, 6)
    (Sunday, 7)
*/

4. 随机一个枚举值，一般用来做测试

 public T RandomEnum<T>()
 { 
     T[] values = (T[]) Enum.GetValues(typeof(T));
     return values[new Random().Next(0,values.Length)];
 }