day8：struts2小demo，实现一个用户登录模块
web.xml：
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_9" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<welcome-file-list>
<welcome-file>Index.jsp</welcome-file>
</welcome-file-list>
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
struts.xml：
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
"http://struts.apache.org/dtds/struts-2.3.dtd">
<struts>
<package name="default" namespace="/" extends="struts-default">
<action name="loginA" class="LoginAction">
<result name="success">
/Welcome.jsp
</result>
<result name="login">
/Index.jsp
</result>
</action>
</package>
</struts>
action:
import com.opensymphony.xwork2.ActionSupport;
public class LoginAction extends ActionSupport{
private String username;
private String password;
/**
* @return username
*/
public String getUsername() {
return username;
}
/**
* @param username 要设置的 username
*/
public void setUsername(String username) {
this.username = username;
}
/**
* @return password
*/
public String getPassword() {
return password;
}
/**
* @param password 要设置的 password
*/
public void setPassword(String password) {
this.password = password;
}
public String execute(){
System.out.println("方法开始执行");
if( "xx".equalsIgnoreCase(username)&&"xxsoft".equals(password) ){
System.out.println("方法执行结束");
return SUCCESS;
}
else
return LOGIN;
}
}
Index.jsp：
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<%@ taglib prefix="s" uri="/struts-tags"%>
<html>
<head>
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>???????</title>
</head>
<body>
<s:form action="loginA">
<s:label value="登录信息"></s:label>
<s:textfield name="username" label="用户名"></s:textfield>
<s:password name="password" label="密码"></s:password>
<s:submit value="登录"></s:submit>
</s:form>
</body>
</html>
Welcome.jsp:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<%@ taglib prefix="s" uri="/struts-tags"%>
<html>
<head>
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>???????</title>
</head>
<body>
登录成功，欢迎您<s:property value="username"></s:property>
</body>
</html>
弱弱的有两个小问题：
1，启动运行后每次都要修改url地址，可有什么办法？
2，tomcat启动中可否对程序做修改后刷新页面查看结果？
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