实验六

实验任务一

#include <stdio.h>
#include <string.h>
#define N 3  

typedef struct student {
    int id;              // 学号
    char name[20];       // 姓名
    char subject[20];    // 考试科目
    double perf;         // 平时成绩
    double mid;          // 期中成绩
    double final;        // 期末成绩
    double total;        // 总评成绩
    char level[10];      // 成绩等级
} STU;


void input(STU[], int);
void output(STU[], int);
void calc(STU[], int);
int fail(STU[], STU[], int);
void sort(STU[], int);

int main() {
    STU st[N], fst[N];   // 数组st记录学生信息，fst记录不及格学生信息
    int k;               // 用于记录不及格学生个数

    printf("录入学生成绩信息:\n");
    input(st, N);

    printf("\n成绩处理...\n");
    calc(st, N);

    k = fail(st, fst, N);
    sort(st, N);
    
    printf("\n学生成绩排名情况:\n");
    output(st, N);

    printf("\n不及格学生信息:\n");
    output(fst, k);

    return 0;
}


void input(STU s[], int n) {
    int i;
    for(i = 0; i < n; i++)
        scanf("%d %s %s %lf %lf %lf", &s[i].id, s[i].name, s[i].subject,
              &s[i].perf, &s[i].mid, &s[i].final);
}


void output(STU s[], int n) {
    int i;
    
    printf("----------------------------------------------------------------\n");
    printf("学号   姓名   科目     平时  期中  期末  总评  等级\n");
    
    for(i = 0; i < n; i++)
        printf("%-6d %-6s %-8s %-4.0f %-4.0f %-4.0f %-4.1f %s\n",
               s[i].id, s[i].name, s[i].subject, 
               s[i].perf, s[i].mid, s[i].final, 
               s[i].total, s[i].level);
}


void calc(STU s[], int n) {
    int i;
    
    for(i = 0; i < n; i++) {
        s[i].total = s[i].perf * 0.2 + 
                     s[i].mid * 0.2 + 
                     s[i].final * 0.6;
        
        if(s[i].total >= 90)
            strcpy(s[i].level, "优");
        else if(s[i].total >= 80)
            strcpy(s[i].level, "良");
        else if(s[i].total >= 70)
            strcpy(s[i].level, "中");
        else if(s[i].total >= 60)
            strcpy(s[i].level, "及格");
        else
            strcpy(s[i].level, "不及格");
    }
}


int fail(STU s[], STU t[], int n) {
    int i, cnt = 0;
    
    for(i = 0; i < n; i++)
        if(s[i].total < 60)
            t[cnt++] = s[i];
    
    return cnt;
}


void sort(STU s[], int n) {
    int i, j;
    STU t;
    
    for(i = 0; i < n-1; i++)
        for(j = 0; j < n-1-i; j++)
            if(s[j].total < s[j+1].total) {
                t = s[j];
                s[j] = s[j+1];
                s[j+1] = t;
            }
}

实验任务二

#include <stdio.h>
#include <string.h>
#define N 10
#define M 80

typedef struct {
    char name[M];    // 书名
    char author[M];  // 作者
} Book;

int main() {
    Book x[N] = { 
        {"《一九八四》", "乔治.奥威尔"},
        {"《美丽新世界》", "赫胥黎"},
        {"《昨日的世界》", "斯蒂芬.茨威格"},
        {"《万历十五年》", "黄仁宇"},
        {"《一只特立独行的猪》", "王小波"},
        {"《百年孤独》", "马尔克斯"},
        {"《查令十字街84号》", "海莲.汉芙"},
        {"《只是孩子》", "帕蒂.史密斯"},
        {"《刀锋》", "毛姆"},
        {"《沉默的大多数》", "王小波"}
    };
    
    Book *ptr;
    int i;
    char author[M];
    int found;
    
    
    printf("---所有图书信息---\n");
    for(ptr = x; ptr < x + N; ++ptr)
        printf("%-30s%-30s\n", ptr->name, ptr->author);
    
    
    printf("\n---按作者查询图书---\n");
    printf("输入作者名: ");
    gets(author);
    
    found = 0;
    for(ptr = x; ptr < x + N; ++ptr)
        if(strcmp(ptr->author, author) == 0) {
            found = 1;
            printf("%-30s%-30s\n", ptr->name, ptr->author);
        }
    
    if(!found)
        printf("暂未收录该作者书籍!\n");
    
    return 0;
}

实验任务三

#include <stdio.h>
#include <stdlib.h>
#define N 80

typedef struct FilmInfo {
    char name[N];         // 片名
    char director[N];     // 导演
    char region[N];       // 制片国家/地区
    int year;             // 上映年份
    struct FilmInfo *next;// 指向下一个结点的指针
} Film;


void output(Film *head);
Film *insert(Film *head, int n);

int main() {
    int n;        
    Film *head;   
    
    head = NULL;
    printf("输入影片数目: ");
    scanf("%d", &n);
    
    
    head = insert(head, n);
    
    
    printf("\n所有影片信息如下:\n");
    output(head);
    
    return 0;
}


Film *insert(Film *head, int n) {
    int i;
    Film *p;
    
    for(i = 1; i <= n; ++i) {
        p = (Film *)malloc(sizeof(Film));
        printf("请输入第%d部影片信息: ", i);
        scanf("%s %s %s %d", p->name, p->director, p->region, &p->year);
        
        
        p->next = head;
        head = p;  
    }
    
    return head;
}


void output(Film *head) {
    Film *p;
    
    p = head;
    while(p != NULL) {
        printf("%-20s %-20s %-20s %d\n", 
               p->name, p->director, p->region, p->year);
        p = p->next;
    }
}

#include <stdio.h>
#include <stdlib.h>
#define N 80

typedef struct FilmInfo{
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct FilmInfo *next;
}Film;


void output(Film *head);
Film *insert(Film *head,int n);

int main(){
    int n;
    Film *head;
    Film *p;
    
    p=(Film *)malloc(sizeof(Film));
    p->next=NULL;
    head=p;
    
    printf("输入影片数目：");
    scanf("%d",&n);
    
    head=insert(head,n);
    
    printf("\n所有影片信息如下：\n");
    output(head);
    
    return 0;
}

Film *insert(Film *head,int n){
    int i;
    Film *p;
    
    for (i=1;i<=n;++i){
        p=(Film*)malloc(sizeof(Film));
        printf("请输入第%d部影片信息：",i);
        scanf("%s %s %s %d",p->name,p->director,p->region,&p->year);
        
        
        p->next=head->next;
        head->next=p;
    }
    
    return head;
}

void output(Film *head){
    Film *p;
    
    p=head->next;
    while(p!=NULL){
        printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year);
        p=p->next;
    }
}

实验任务四

#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20];          // isbn号
    char name[80];          // 书名
    char author[80];        // 作者
    double sales_price;     // 售价
    int  sales_count;       // 销售册数
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
     Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                  {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
                  {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                  {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 
                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                  {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
    
    printf("图书销量排名(按销售册数): \n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
    
    return 0;
}


void output(Book x[], int n) {
    int i;
    for (i = 0; i < n; i++) {
        printf("%s %s %s %.2f %d\n", 
           x[i].isbn, x[i].name, x[i].author, 
           x[i].sales_price, x[i].sales_count);
    }
}



void sort(Book x[], int n){
    int i,j;
    
    for (i = 0; i < n-1; i++) {
        for (j = 0; j < n-1-i; j++) {
            if (x[j].sales_count < x[j+1].sales_count) {
                Book temp = x[j];
                x[j] = x[j+1];
                x[j+1] = temp;
            }
        }
    }
}


double sales_amount(Book x[], int n){
    double total=0;
    int i;
    
    for (i=0;i<n;i++){
        total+=x[i].sales_price * x[i].sales_count;
    }
    return total;
}

实验任务五

#include <stdio.h>
typedef struct {
    int year;
    int month;
    int day;
} Date;

void input(Date *pd); 
int day_of_year(Date d); 
int compare_dates(Date d1, Date d2); 

void test1() {
    Date d;
    int i;

    printf("输入日期: (以形如2025-12-19这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;

    printf("输入Alice和Bob出生日期: (以形如2025-12-19这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);

        if(ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if(ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main() {
    printf("测试1: 输入日期，打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2：两个人年龄大小关系\n");
    test2();
    
    return 0;
}

void input(Date *pd) {
    scanf("%d-%d-%d", &pd->year, &pd->month, &pd->day);
}


int is_leap(int year) {
    return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
}


int day_of_year(Date d) {
    int days_in_month[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    int total_days = 0;
    int i;

    if(is_leap(d.year)) {
        days_in_month[1] = 29;
    }

    for(i = 0; i < d.month - 1; i++) {
        total_days += days_in_month[i];
    }

    total_days += d.day;
    
    return total_days;
}

int compare_dates(Date d1, Date d2) {

    if(d1.year < d2.year) return -1;
    if(d1.year > d2.year) return 1;
    
    if(d1.month < d2.month) return -1;
    if(d1.month > d2.month) return 1;
    
    if(d1.day < d2.day) return -1;
    if(d1.day > d2.day) return 1;

    return 0;
}

实验任务六

#include <stdio.h>
#include <string.h>

enum Role {admin, student, teacher};

typedef struct {
    char username[20]; 
    char password[20]; 
    enum Role type; 
} Account;

void output(Account x[], int n); 

int main() {
    Account x[] = {{"A1001", "123456", student},
                  {"A1002", "123abcdef", student},
                  {"A1009", "xyz12121", student},
                  {"X1009", "9213071x", admin},
                  {"C11553", "129dfg32k", teacher},
                  {"X3005", "921kfmg917", student}};

    int n;
    n = sizeof(x)/sizeof(Account);
    output(x, n);

    return 0;
}

void output(Account x[], int n) {
    int i, j;
    
    for(i = 0; i < n; i++) {
        printf("%-10s", x[i].username);
        int len = strlen(x[i].password);
        for(j = 0; j < len; j++) {
            printf("*");
        }
        printf("   ");
        switch(x[i].type) {
            case admin:   printf("admin"); break;
            case student: printf("student"); break;
            case teacher: printf("teacher"); break;
        }
        printf("\n");
    }
}

实验任务七

#include <stdio.h>
#include <string.h>

typedef struct {
    char name[20]; 
    char phone[12]; 
    int vip; 
} Contact;

void set_vip_contact(Contact x[], int n, char name[]); 
void output(Contact x[], int n); 
void display(Contact x[], int n); 

#define N 10
int main() {
    Contact list[N] = {{"刘一", "15510846604", 0},
                      {"陈二", "18038747351", 0},
                      {"张三", "18853253914", 0},
                      {"李四", "13230584477", 0},
                      {"王五", "15547571923", 0},
                      {"赵六", "18856659351", 0},
                      {"周七", "17705843215", 0},
                      {"孙八", "15552933732", 0},
                      {"吴九", "18077702405", 0},
                      {"郑十", "18820725036", 0}};

    int vip_cnt, i;
    char name[20];

    printf("显示原始通讯录信息：\n");
    output(list, N);

    printf("\n输入要设置的紧急联系人个数：");
    scanf("%d", &vip_cnt);
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for(i = 0; i < vip_cnt; ++i) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }

    printf("\n显示通讯录列表：(按姓名字典序升序排列，紧急联系人最先显示)\n");
    display(list, N);

    return 0;
}
void set_vip_contact(Contact x[], int n, char name[]) {
    int i;
    
    for(i = 0; i < n; i++) {
        if(strcmp(x[i].name, name) == 0) {
            x[i].vip = 1;
            break; 
        }
    }
}

void display(Contact x[], int n) {
    int i, j;
    Contact temp;
    for(i = 0; i < n-1; i++) {
        for(j = i+1; j < n; j++) {
            int need_swap = 0;
            
            if(x[i].vip < x[j].vip) {
                need_swap = 1;
            } else if(x[i].vip == x[j].vip) {
                if(strcmp(x[i].name, x[j].name) > 0) {
                    need_swap = 1;
                }
            }
            
            if(need_swap) {
                temp = x[i];
                x[i] = x[j];
                x[j] = temp;
            }
        }
    }
    for(i = 0; i < n; i++) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if(x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}
void output(Contact x[], int n) {
    int i;
    for(i = 0; i < n; ++i) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if(x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}