C语言_柔性数组的使用

struct S
{
	int n;
	int arr[];//柔性数组成员
};


int main()
{
	//柔性数组的使用
	struct S * ps =(struct S*)malloc(sizeof(struct S)+40);
	if (ps == NULL)
	{
		return 1;
	}
	ps->n = 100;
	int i = 0;
	for (i = 0; i < 10; i++)
	{
		ps->arr[i] = i;
	}
	for (i = 0; i < 10; i++)
	{
		printf("%d ",ps->arr[i]);
	}
	struct S* ptr = (struct S*)realloc(ps, sizeof(struct S) + 80);
	if (ptr != NULL)
	{
		ps = ptr;
		ptr = NULL;
	}
	free(ps);
	ps = NULL;
	return 0;
}