165 Compare Version Numbers

165 Compare Version Numbers

用python处理字符串还是比较简单的

class Solution:
    # @param {string} version1
    # @param {string} version2
    # @return {integer}
    def compareVersion(self, version1, version2):
        v1 = [int(v) for v in version1.split(".")]
        v2 = [int(v) for v in version2.split(".")]
        v1 += [0] * (len(v2) - len(v1))
        v2 += [0] * (len(v1) - len(v2))
        return 1 if v1 > v2 else (-1 if v1 < v2 else 0)