【Python】文件路径

https://blog.csdn.net/dingmanzzz/article/details/113449275

 

if __name__ == '__main__':
    pa = r'C:\Users\hha\Desktop\002594.txt'

    # 获取文件路径
    print(os.path.dirname(pa))  # C:\Users\hha\Desktop

    # 获取文件名
    print(os.path.basename(pa))  # 002594.txt

    # 路径与文件名合成
    print(os.path.join(os.path.dirname(pa), os.path.basename(pa)))  # C:\Users\hha\Desktop\002594.txt