@ImportResource原生配置文件引入

xml配置文件

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

    <bean id="userxml" class="com.example.studywork1.pojo.User">
        <constructor-arg index="0" value="张三"/>
        <constructor-arg index="1" value="18"/>
        <property name="name" value="张三"></property>
        <property name="age" value="18"></property>
    </bean>

    <bean id="infoxml" class="com.example.studywork1.pojo.Info">
        <constructor-arg index="0" value="长春"/>
        <constructor-arg index="1" value="男"/>
        <property name="address" value="长春"></property>
        <property name="sex" value="男"></property>
    </bean>
</beans>

配置类

@Component
@ImportResource("classpath:myBean.xml")
public class MyConfig1 {

}
@Data
public class Info {

    private String address;

    private String sex;

    public Info(String address, String sex) {
        this.address = address;
        this.sex = sex;
    }
}
@Data
public class User {

    private String name;

    private int age;

    public User(String name, int age) {
        this.name = name;
        this.age = age;
    }
}

输出类

@SpringBootApplication
public class StudyWork1Application {

    public static void main(String[] args) {
        ConfigurableApplicationContext run = SpringApplication.run(StudyWork1Application.class, args);
        String[] names = run.getBeanNamesForType(User.class);
        for (String name : names) {
            System.out.println("user类型:"+name);
        }
        String[] names1 = run.getBeanNamesForType(Info.class);
        for (String s : names1) {
            System.out.println("info类型:"+s);
        }
    }
}

输出结果

 

posted @ 2022-07-09 08:51  Dabo丶  阅读(37)  评论(0编辑  收藏  举报