递归大总结之打印大数1-n

递归

#include<iostream>
using namespace std;
void PrintfNumber(char num[])
{
	bool isBegin0 = true;
	int nlength = strlen(num);
	for (int i = 0; i < nlength; ++i)
	{
		if (isBegin0&&num[i] != '0')
		{
			isBegin0 = false;
		}
		if (!isBegin0)
		{
			cout << num[i];
		}
	}
}
void PrintToMaxDigits2(char *num, int length, int index)
{
	if (index == length - 1)
	{
		PrintfNumber(num);
		return;
	}
	for (int i = 0; i < 10; i++)
	{
		num[index + 1] = i + '0';
		PrintToMaxDigits2(num, length, index + 1);//
	}
}
void PrintToMaxofDigits(int n)
{
	if (n <= 0)
	{
		return;
	}
	char *num = new char[n + 1];
	num[n] = '\0';
	for (int i = 0; i < 10; i++)
	{
		num[0] = i + '0';
		PrintToMaxDigits2(num, n, 0);
	}
}
int main()
{
	int n;
	cin >> n;
	PrintToMaxofDigits(n);
	system("pause");
}
详解

//以n等于3为例
void PrintToMaxDigits2(char *num, int length, int index)
{
	if (index == length - 1)
	{
		PrintfNumber(num);
		return;
	}
	for (int i = 0; i < 10; i++)
	{
		num[index + 1] = i + '0';
		PrintToMaxDigits2(num, length, index + 1);//
		/*
		index=1;
		for (int i = 0; i < 10; i++)
		{
			num[index + 1] = i + '0';
			PrintToMaxDigits2(num, 3, index + 1);
					if (index == length - 1)
					{
						//打印了1-9,这时num[1]还是1,当num[1]是2时再打印1-9
						PrintfNumber(num);
						
						return;
					}
		
		}

		*/
	}
}






posted @ 2017-03-08 21:21  乐天的java  阅读(41)  评论(0)    收藏  举报