AcWing850.Dijkstra求最短路 II

题解
#include <iostream>
#include <cstring>
#include <queue>
#include <vector>
using namespace std;
const int N = 1e6 + 10;
typedef pair<int,int> PII;
bool flag[N];
int d[N];
int h[N], e[N], ne[N], v[N], idx;
void add(int x, int y, int z)
{
ne[idx] = h[x], h[x] = idx, e[idx] = y, v[idx++] = z;
}
void Dijkstra()
{
memset(d, 0x3f, sizeof d);
d[1] = 0;
priority_queue<PII, vector<PII>, greater<PII>> q;
q.push({d[1], 1});
while(q.size())
{
int head = q.top().second, distance = q.top().first;
q.pop();
if(flag[head]) continue;
flag[head] = true;
for(int i = h[head]; ~i; i = ne[i])
if(!flag[e[i]] && distance + v[i] < d[e[i]])
d[e[i]] = v[i] + distance, q.push({d[e[i]], e[i]});
}
}
int main()
{
memset(h, -1, sizeof h);
int n, m, x, y, z;
scanf("%d%d",&n,&m);
for(int i = 1; i <= m; ++i)
scanf("%d%d%d",&x,&y,&z), add(x, y, z);
Dijkstra();
if(flag[n])
cout << d[n] << endl;
else
cout << -1 << endl;
return 0;
}