AcWing839. 模拟堆

题解
#include <iostream>
using namespace std;
const int N = 1e5+10;
//hp:堆中下标k,集合中下标为hp[k]
//ph:集合中下标k,堆中下标ph[k]
int p[N], h[N], hp[N], ph[N], cnt, sz;
void heap_swap(int a, int b)
{
swap(ph[hp[a]], ph[hp[b]]);
swap(hp[a], hp[b]);
swap(h[a], h[b]);
}
void down(int u)
{
int t = u;
if(u * 2 <= sz && h[u * 2] < h[t]) t = u * 2;
if(u * 2 + 1 <= sz && h[u * 2 + 1] < h[t]) t = u * 2 + 1;
if(u != t)
{
heap_swap(t, u);
down(t);
}
}
void up(int u)
{
while(u / 2 && h[u / 2] > h[u])
{
heap_swap(u, u/2);
u /= 2;
}
}
int main()
{
int n, k, x;
string c;
scanf("%d",&n);
while(n --)
{
cin >> c;
if(c == "I")
{
scanf("%d", &k);
h[++sz] = k;
p[++cnt] = k;
hp[sz] = cnt;
ph[cnt] = sz;
up(sz);
}
else if(c == "PM") printf("%d\n",h[1]);
else if(c == "DM")
{
heap_swap(1, sz);
sz -- ;
down(1);
}
else if(c == "D")
{
scanf("%d",&k);
k = ph[k];
heap_swap(k, sz);
sz -- ;
down(k);
up(k);
}
else{
scanf("%d%d", &k, &x);
h[ph[k]] = x;
down(ph[k]);
up(ph[k]);
}
}
return 0;
}