【前缀和】Acwing795.前缀和
Acwing795.前缀和

题解
#include <iostream>
#include <cstdio>
using namespace std;
const int N = 1e5+10;
int a[N];
int main()
{
int n, m;
scanf("%d%d",&n,&m);
int x, y;
for(int i = 1; i <= n; ++i){
scanf("%d",&x);
a[i] = a[i-1] + x;
}
while(m -- )
{
scanf("%d%d",&x,&y);
printf("%d\n",a[y] - a[x-1]);
}
return 0;
}

浙公网安备 33010602011771号