摘要: 程序: 方法1: 1 #include <stdio.h> 2 #define N 10000 3 int main(){ 4 long n, temp; 5 long mask=1; 6 scanf("%ld", &n); 7 temp = n; 8 while(temp/10 != 0){ 9 阅读全文
posted @ 2019-04-16 22:47 cxc1357 阅读(1334) 评论(0) 推荐(0)
摘要: 程序: 1 #include<stdio.h> 2 3 int main() { 4 int i,n,s = 1; 5 scanf("%d",&n); 6 for(i=1; i<n; i++) { 7 s = (s+1)*2; 8 } 9 printf("%d",s); 10 } 阅读全文
posted @ 2019-04-16 22:00 cxc1357 阅读(720) 评论(0) 推荐(0)
摘要: 程序: 1 #include<stdio.h> 2 3 int main() { 4 int i,n; 5 double fz = 1,fm = 0,sum = 2; 6 scanf("%d",&n); 7 double s = 0; 8 for(i = 1; i <= n; i++) { 9 fm 阅读全文
posted @ 2019-04-16 21:48 cxc1357 阅读(644) 评论(0) 推荐(0)
摘要: 程序: 1 #include<stdio.h> 2 #include<math.h> 3 int prime(int p); 4 5 int main() { 6 int m,n,i; 7 int sum = 0; 8 int count = 0; 9 scanf("%d %d",&m,&n); 1 阅读全文
posted @ 2019-04-16 20:56 cxc1357 阅读(1079) 评论(0) 推荐(0)