• 博客园logo
  • 会员
  • 众包
  • 新闻
  • 博问
  • 闪存
  • 赞助商
  • HarmonyOS
  • Chat2DB
    • 搜索
      所有博客
    • 搜索
      当前博客
  • 写随笔 我的博客 短消息 简洁模式
    用户头像
    我的博客 我的园子 账号设置 会员中心 简洁模式 ... 退出登录
    注册 登录
村雨sup
自己选的路,跪着也要走完 XD
博客园    首页    新随笔    联系   管理    订阅  订阅
PAT 1008 Elevator
1008 Elevator (20 分)
 

The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.

For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100.

Output Specification:

For each test case, print the total time on a single line.

Sample Input:

3 2 3 1

Sample Output:

41
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;



int main(){
    int n;
    cin >> n;
    int sum = n*5;
    int cur = 0;

    for(int i=0;i < n;i++){
        int x; cin >> x;
        int t = x-cur;
        sum += (t>0)?t*6:(-t)*4;
        cur = x;
    }
    cout << sum;


    return 0;
}

?这题也太水了吧

 
posted on 2019-04-10 00:26  村雨sup  阅读(119)  评论(0)    收藏  举报
刷新页面返回顶部
博客园  ©  2004-2025
浙公网安备 33010602011771号 浙ICP备2021040463号-3