摘要:
这是廖の码,用埃式筛法求得素数 def _odd_iter(): n = 1 while True: n = n + 2 yield ndef _not_divisible(n): return lambda x: x % n > 0def primes(): yield 2 it = _odd_i 阅读全文
摘要:
def findMinAndMax(s): min=99999 max=-99999 if s: for i in s: if i<min: min=i if i>max: max=i return (min,max) else: return(None,None)# 测试if findMinAnd 阅读全文