STM32 在keil下进行strtol函数的功能测试

STM32 在keil下进行strtol函数的功能测试

源码：

void test_str2num_strtol(void)
{
    int a;
    printf("\r\n\r\n0x1234 = %d,",strtol("0x1234",NULL,0));
    printf("\r\n1234 = %d,",strtol("1234",NULL,0));
    printf("\r\nHex:1234 = %d,",strtol("1234",NULL,16));
    printf("\r\n0 = %d,",strtol("0",NULL,0));
    printf("\r\n01234 = %d,",strtol("01234",NULL,0));
    printf("\r\n0.1234 = %d,",strtol("0.1234",NULL,0));
    printf("\r\n-1234 = %d,",strtol("-1234",NULL,0));
    printf("\r\n1234ab = %d,",strtol("1234ab",NULL,0));
    printf("\r\n0b1011 = %d,",strtol("0b1011",NULL,0));
    printf("\r\nbin:0b1011 = %d,",strtol("0b1011",NULL,2));
    printf("\r\nbin:1011 = %d,",strtol("1011",NULL,2));
    printf("\r\n0xB = %d,",strtol("0xB",NULL,0));
    printf("\r\nabc1234 = %d,\r\n",strtol("abc1234",NULL,0));
}

输出：

0x1234 = 4660,
1234 = 1234,
Hex:1234 = 4660,
0 = 0,
01234 = 668,
0.1234 = 0,
-1234 = -1234,
1234ab = 1234,
0b1011 = 0,
bin:0b1011 = 0,
bin:1011 = 11,
0xB = 11,
abc1234 = 0,

可以看出，这个函数:

如果最后一个参数设置为0的话，会默认把字符串当作10进制进行转换;

如果0x开头，则以16进制转换;

如果以0开头，则以8进制进行转换;

如果最后一个参数为 2 的话,那么就会以二进制转换;

如果是16则以16进制进行转换。

出错，就返回0.

如果以其他字符开头，则以出错返回0.

如果后面有不可识别的字符，则只转换前面的数字。