实验6

task1.c

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#define N 3 // 运行程序输入测试时，可以把这个数组改小一些输入测试
typedef struct student {
    int id; // 学号
    char name[20]; // 姓名
    char subject[20]; // 考试科目
    double perf; // 平时成绩
    double mid; // 期中成绩
    double final; // 期末成绩
    double total; // 总评成绩
    char level[10]; // 成绩等级
} STU;
void input(STU[], int); // 录入学生信息
void output(STU[], int); // 输出学生信息
void calc(STU[], int); // 计算总评和等级
int fail(STU[], STU[], int); // 统计不及格学生信息
void sort(STU[], int); // 排序
int main() {
    STU st[N], fst[N]; // 数组st记录学生信息，fst记录不及格学生信息
    int k; // 用于记录不及格学生个数
    printf("录入学生成绩信息:\n");
    input(st, N);
    printf("\n成绩处理...\n");
    calc(st, N);
    k = fail(st, fst, N);
    sort(st, N);
    printf("\n学生成绩排名情况:\n");
    output(st, N);
    printf("\n不及格学生信息:\n");
    output(fst, k);
    return 0;
}
void input(STU s[], int n) {
    int i;
    for (i = 0; i < n; i++)
        scanf("%d %s %s %lf %lf %lf", &s[i].id, s[i].name, s[i].subject,
            &s[i].perf, &s[i].mid, &s[i].final);
}
void output(STU s[], int n) {
    int i;
    printf("-----------------\n");
    printf("学号 姓名 科目 平时 期中 期末 总评 等级\n");
    for (i = 0; i < n; i++)
        printf("%d %-6s %-4s %-4.0f %-4.0f %-4.0f %-4.1f %s\n",s[i].id,s[i].name,s[i].subject,s[i].perf,s[i].mid,s[i].final,s[i].total, s[i].level);
}
void calc(STU s[], int n) {
    int i;
    for (i = 0; i < n; i++) {
        s[i].total = s[i].perf * 0.2 +
            s[i].mid * 0.2 +
            s[i].final * 0.6;
        if (s[i].total >= 90)
            strcpy(s[i].level, "优");
        else if (s[i].total >= 80 && s[i].total < 90)
            strcpy(s[i].level, "良");
        else if (s[i].total >= 70 && s[i].total < 80)
            strcpy(s[i].level, "中");
        else if (s[i].total >= 60 && s[i].total < 70)
            strcpy(s[i].level, "及格");
        else
            strcpy(s[i].level, "不及格");
    }
}
int fail(STU s[], STU t[], int n) {
    int i, cnt = 0;
    for (i = 0; i < n; i++)
        if (s[i].total < 60)
            t[cnt++] = s[i];
    return cnt;
}
void sort(STU s[], int n) {
    int i, j;
    STU t;
    for (i = 0; i < n - 1; i++)
        for (j = 0; j < n - 1 - i; j++)
            if (s[j].total < s[j + 1].total) {
                t = s[j];
                s[j] = s[j + 1];
                s[j + 1] = t;
            }
}

 

 

task2.c

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#define N 10
#define M 80
typedef struct {
    char name[M]; // 书名
    char author[M]; // 作者
} Book;
int main() {
    Book x[N] = { {"《一九八四》", "乔治.奥威尔"},
    {"《美丽新世界》", "赫胥黎"},
    {"《昨日的世界》", "斯蒂芬.茨威格"},
    {"《万历十五年》", "黄仁宇"},
    {"《一只特立独行的猪》", "王小波"},
    {"《百年孤独》", "马尔克斯"},
    {"《查令十字街84号》", "海莲.汉芙"},
    {"《只是孩子》", "帕蒂.史密斯"},
    {"《刀锋》", "毛姆"},
    {"《沉默的大多数》", "王小波"} };
    Book* ptr;
    int i;
    char author[M];
    // 使用指针遍历结构体数组
    printf("所有图书信息: \n");
    for (ptr = x; ptr < x + N; ++ptr)
        printf("%-30s%-30s\n", ptr->name, ptr->author);
    // 查找指定作者的图书
    printf("\n输入作者名: ");
    gets_s(author);
    for (ptr = x; ptr < x + N; ++ptr)
        if (strcmp(ptr->author, author) == 0) {
            printf("%-30s%-30s\n", ptr->name, ptr->author);
        }
    return 0;
}

 task3_1.c

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#define N 80
typedef struct FilmInfo {
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct FilmInfo* next;
} Film;
void output(Film* head); // 遍历输出链表信息
Film* insert(Film* head, int n); // 向链表中插入n个结点，返回头指针
int main() {
    int n; // 结点数
    Film* head; // 头指针变量，存放链表中第一个节点的地址
    head = NULL;
    printf("输入影片数目: ");
    scanf("%d", &n);
    // 向链表中插入n部影片信息
    head = insert(head, n);
    // 遍历输出链表中所有影片信息
    printf("\n所有影片信息如下: \n");
    output(head);
    return 0;
}
// 向链表中插入n个结点，从表头插入，返回头指针变量
Film* insert(Film* head, int n) {
    int i;
    Film* p;
    for (i = 1; i <= n; ++i) {
        p = (Film*)malloc(sizeof(Film));
        printf("请输入第%d部影片信息: ", i);
        scanf("%s %s %s %d", p->name, p->director, p->region, &p->year);
        // 把结点从表头插入到链表中
        p->next = head;
        head = p; // 更新头指针变量
    }
    return head;
}
// 遍历输出链表信息
void output(Film* head) {
    Film* p;
    p = head;
    while (p != NULL) {
        printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p -> year);
        p = p->next;
    }
}

 

 task3_2.c

#define _CRT_SEUCRE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#define N 80
typedef struct FilmInfo {
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct FilmInfo* next;
} Film;
void output(Film* head); // 遍历输出链表信息
Film* insert(Film* head, int n); // 向链表中插入n个结点，返回头指针
int main() {
    int n; // 结点数
    Film* head; // 头指针变量，存放链表中第一个节点的地址
    Film* p; // 存放新申请的Film节点内存空间地址
    // 创建头结点
    p = (Film*)malloc(sizeof(Film));
    p->next = NULL;
    head = p; // 头指针变量存放头节点的地址
    printf("输入影片数目: ");
    scanf("%d", &n);
    // 向链表中插入n部影片信息
    head = insert(head, n);
    // 遍历输出链表中所有影片信息
    printf("\n所有影片信息如下: \n");
    output(head);
    return 0;
}
// 向链表中插入n个结点，从表头插入，返回头指针变量
Film* insert(Film* head, int n) {
    int i;
    Film* p;
    for (i = 1; i <= n; ++i) {
        p = (Film*)malloc(sizeof(Film));
        printf("请输入第%d部影片信息: ", i);
        scanf("%s %s %s %d", p->name, p->director, p->region, &p->year);
        // 把结点从表头插入到链表中
        p->next = head->next;
        head->next = p;
    }
    return head;
}
// 遍历输出链表信息
void output(Film* head) {
    Film* p;
    p = head->next;
    while (p != NULL) {
        printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p -> year);
        p = p->next;
    }
}

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
#define N 10
typedef struct {
    char isbn[20];
    char name[80];
    char author[80];
    double sales_price;
    int sales_count;
}Book;
void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);
int main() {
    Book x[N]= {{ "978-7-229-14156-1", "源泉", "安.兰德", 84, 59 },
    { "978-7-5133-5261-1", "李白来到旧金山", "谭夏阳", 48, 16 },
    { "978-7-5617-4347-8", "陌生人日记", "周怡芳", 72.6, 27 },
    { "978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49 },
    { "978-7-5046-9568-0", "数据化决策", "道格拉斯·W·哈伯德", 49, 42 },
    { "978-7-5133-4388-6", "美好时代的背后", "凯瑟琳.布", 34.5, 39 },
    { "978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55 },
    { "978-7-5321-5691-7", "何为良好生活", "陈嘉映", 29.5 , 31 },
    { "978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42 },
    { "978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44 }};
    printf("图书销量排名:\n");
    sort(x, N);
    output(x, N);
    printf("\n图书销售总额:%.2f\n", sales_amount(x, N));
    return 0;
}
void output(Book x[], int n)
{int i = 0;
for (i = 0; i < n; i++)
    printf("%s %-28s %-24s %-15lf %d\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
}
void sort(Book x[], int n) {
    int i = 0, j = 0;
    Book t;
    for (i = 0; i < n - 1; i++)
        for (j = 0; j < n - i - 1; j++)
            if (x[j].sales_count < x[j + 1].sales_count)
            {
                t = x[j];
                x[j] = x[j + 1];
                x[j + 1] = t;
            }

                
}
double sales_amount(Book x[], int n) {
    int i = 0, j = 0;
    double sum = 0;
    for (i = 0; i < n; i++)
        sum = sum + (double)(x[i].sales_count * x[i].sales_price);
    return sum;
}

task5.c

#include <stdio.h>

typedef struct {
    int year;
    int month;
    int day;
} Date;

void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);

void test1() {
    Date d;
    int i;

    printf("输入日期:(以形如2023-12-11这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;

    printf("输入Alice和Bob出生日期:(以形如2023-12-11这样的形式输入)\n");
    for(i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);

        if(ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if(ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main() {
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
}

void input(Date *pd) {
    scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
}

int day_of_year(Date d) {
    int date=0;
    switch(d.month)
    {
        case 1:date=d.day;break;
        case 2:date=31+d.day;break;
        case 3:date=60+d.day;break;
        case 4:date=91+d.day;break;
        case 5:date=121+d.day;break;
        case 6:date=152+d.day;break;
        case 7:date=182+d.day;break;
        case 8:date=213+d.day;break;
        case 9:date=244+d.day;break;
        case 10:date=274+d.day;break;
        case 11:date=305+d.day;break;
        case 12:date=335+d.day;break;
    }
    if (d.year%4!=0&&d.month>2)
        date--;
    return date;
}

int compare_dates(Date d1, Date d2) {
    int ans;
    if (d1.year<d2.year)
        ans=-1;
    else if (d1.year>d2.year)
        ans=1;
    else
    {
        if (d1.month<d2.month)
            ans=-1;
        else if (d1.month>d2.month)
            ans=1;
        else
        {
            if (d1.day<d2.day)
                ans=-1;
            else if (d1.day>d2.day)
                ans=1;
            else
                ans=0;
        }
    }
    return ans;
}

 task6.c

#include <stdio.h>
#include <string.h>

enum Role {admin, student, teacher};

typedef struct {
    char username[20];
    char password[20];
    enum Role type;
} Account;

void output(Account x[], int n);

int main() {
    Account x[] = {{"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student},
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student}};
    int n;
    n = sizeof(x)/sizeof(Account);
    output(x, n);

    return 0;
}

void output(Account x[], int n) {
    int i,j;
    for (i=0;i<n;i++)
    {
        printf("%-20s",x[i].username);
        for (j=0;j<strlen(x[i].password);j++)
            printf("*");
        for (;j<20;j++)
            printf(" ");
        switch(x[i].type)
        {
            case 0:printf("admin");break;
            case 1:printf("student");break;
            case 2:printf("teacher");break;
        }
        printf("\n");
    }
}