实验1

task1_1.c
//打印两个水平排列的字符小人

include<stdio.h>

int main()
{

printf(" o   o \n");
printf("<H> <H>\n");
printf("I I I I\n");

return 0;

}
task1_2.c
//在水平方向上打印出两个字符小人

include <stdio.h>

int main()
{
printf(" O O \n");
printf(" \n");
printf("I I I I\n");
return 0;
}
task2.c
// 从键盘上输入三个数据作为三角形边长，判断其能否构成三角形
// 构成三角形的条件：任意两边之和大于第三边

include <stdio.h>

int main()
{
double a, b, c;

// 输入三边边长
scanf("%lf%lf%lf", &a, &b, &c);

// 判断能否构成三角形
// 补充括号里的逻辑表达式
if ((a + b > c) && (a + c > b) && (b + c > a))
    printf("能构成三角形\n");
else
    printf("不能构成三角形\n");

return 0;

}
task3.c

include <stdio.h>

int main()
{
char ans1, ans2;

printf("每次课前认真预习、课后及时复习了没？(输入y或Y表示有,输入n或N表示没有) : ");
ans1 = getchar(); 
 
getchar(); 

printf("\n动手敲代码实践了没？(输入y或Y表示敲了,输入n或N表示木有敲) : ");
ans2 = getchar();

if ((ans1 == 'y' || ans1 == 'Y') && (ans2 == 'y' || ans2 == 'Y'))
printf("\n罗马不是一天建成的，继续保持哦:)\n");
else
printf("\n罗马不是一天毁灭的，我们来建设吧\n");

return 0;

}
没有第9行时，getchar会丢弃换行符，造成结果不准确
task4.c

include <stdio.h>

int main()
{
double x, y;
char c1, c2, c3;
int a1, a2, a3;

scanf("%d%d%d", &a1, &a2, &a3); 
printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3);

// 使用空格忽略空白字符
scanf(" %c %c %c", &c1, &c2, &c3); 
printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);

scanf("%lf%lf", &x, &y); 
printf("x = %lf, y = %lf\n", x, y);

return 0;

}
task5.c
// 计算10亿秒约等于多少年，并打印输出

include <stdio.h>

int main()
{
int year;
// 10亿秒
long long total_seconds = 1000000000;
// 一年的秒数
int seconds_per_year = 365 * 24 * 3600;
// 计算年数，使用整数除法，自动舍去小数部分
year = total_seconds / seconds_per_year;
// 四舍五入处理
if ((total_seconds % seconds_per_year * 2 >= seconds_per_year))
{
year++;
}

printf("10亿秒约等于%d年\n", year);
return 0;

}
task6_2.c

include <stdio.h>

include <math.h>

int main()
{
double x, ans;

while(scanf("%1f", &x) != EOF)
{
ans = pow(x, 365);
printf("%.2f的365次方: %.2f\n", x, ans);
printf("\n");
}

return 0;

}
task7.c

include <stdio.h>

int main() {
double c;
while (scanf("%lf", &c) == 1) {
double f = (9.0 / 5) * c + 32;
printf("摄氏度c = %.2lf时, 华氏度f = %.2lf\n", c, f);
}
return 0;
}
task8.c

include <stdio.h>

include <math.h>

int main() {
double a, b, c;
while (scanf("%lf %lf %lf", &a, &b, &c) == 3) {
double s = (a + b + c) / 2.0;
double area = sqrt(s * (s - a) * (s - b) * (s - c));
printf("%.3f\n", area);
}
return 0;
}