Day3

 

 

 

 3.代码示例

#include<iostream> 
using namespace std;
int main(){
    int year,month,day,sum,s=0,i,q;
    cin>>year>>month>>day;
    int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
    if((year%4==0&&year%100!=0)||(year%400==0))
    {
        a[2]=29;
    }
    if((year-1990)%4<3){    
    sum=((year-1990)/4)*1461+(year-1990)%4*365;    
}
else
{
    sum=((year-1990)/4)*1461+(year-1990)%4*365+1;    
}
for(i=1;i<month;i++){
    s+=a[i];
}
q=sum+s+day;
if(q%5<4&&q%5>0)
cout<<"今天打鱼"; 
else
cout<<"今天晒网";
cout<<q;
    return 0;
}

4.结果输出