在链表中找到第一个含有某值的结点并且删除该结点. 

 1 void RemoveNode(ListNode** pHead,int value)
 2 {
 3     if(pHead==NULL||*pHead==NULL)
 4         return;
 5     ListNode* pToBeDeleted = NULL;
 6     if((*pHead)->m_nValue==value)
 7     {
 8         pToBeDeleted=*pHead;
 9         *pHead=(*pHead)->m_pNext;
10     }
11     else
12     {
13         ListNode* pNode= *pHead;
14         while(pNode->m_pNext!=NULL&&pNode->m_pNext->m_nValue!=value)
15             pNode=pNode->m_pNext;
16         if(pNode->m_pNext!=NULL&&pNode->m_pNext->m_nValue==value)
17         {
18             pToBeDeleted=pNode->m_pNext;
19             pNode->m_pNext=pNode->m_pNext->m_pNext;
20 
21         }
22     }
23     if(pToBeDeleted!=NULL)
24     {
25         delete pToBeDeleted;
26         pToBeDeleted=NULL;
27     }
28 }

 

posted @ 2014-01-19 11:50  CrazyCode.  阅读(215)  评论(0)    收藏  举报