d = [('a', 24), ('g', 52), ('i', 12)]
print(sorted(d),key = lambda x:x[1])
sorted (字典,排序的依据: 字典[key])
posted on 2019-06-29 08:57 卓达 阅读(315) 评论(0) 编辑 收藏 举报
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