Ural 1960 Palindromes and Super Abilities

Palindromes and Super Abilities

Time Limit: 1000ms

Memory Limit: 65536KB

This problem will be judged on Ural. Original ID: 1960
64-bit integer IO format: %lld      Java class name: (Any)

After solving seven problems on Timus Online Judge with a word “palindrome” in the problem name, Misha has got an unusual ability. Now, when he reads a word, he can mentally count the number of unique nonempty substrings of this word that are palindromes.

Dima wants to test Misha’s new ability. He adds letters s1, ..., sn to a word, letter by letter, and after every letter asks Misha, how many different nonempty palindromes current word contains as substrings. Which n numbers will Misha say, if he will never be wrong?

 

Input

The only line of input contains the string s1...sn, where si are small English letters (1 ≤ n ≤ 105).

 

Output

Output n numbers separated by whitespaces, i-th of these numbers must be the number of different nonempty substrings of prefix s1...si that are palindromes.

 

Sample Input

aba

Sample Output

1 2 3

Source

Ural FU contest. Kontur Cup. Petrozavodsk training camp. Winter 2013

 

解题：PalindromicTree

#include <bits/stdc++.h>
using namespace std;
const int maxn = 100010;
struct PalindromicTree{
    int fail[maxn],len[maxn],son[maxn][26];
    int tot,last,n;
    char s[maxn];
    int newnode(int slen = 0){
        memset(son[tot],0,sizeof son[tot]);
        len[tot] = slen;
        return tot++;
    }
    void init(){
        n = tot = last = 0;
        newnode(0);
        newnode(-1);
        fail[1] = fail[0] = 1;
        s[n] = -1;
    }
    int getFail(int x){
        while(s[n - len[x] - 1] != s[n]) x = fail[x];
        return x;
    }
    void extend(int c){
        s[++n] = c;
        int cur = getFail(last);
        if(!son[cur][c]){
            int x = newnode(len[cur] + 2);
            fail[x] = son[getFail(fail[cur])][c];
            son[cur][c] = x;
        }
        last = son[cur][c];
    }
}pt;
char str[maxn];
int main(){
    while(~scanf("%s",str)){
        pt.init();
        bool flag = false;
        for(int i = 0; str[i]; ++i){
            pt.extend(str[i] - 'a');
            if(flag) putchar(' ');
            printf("%d",pt.tot - 2);
            flag = true;
        }
        putchar('\n');
    }
    return 0;
}