javascript中if下使用style.display

<script language=javascript>
function showclasscheck(checktype)
{
var objDiv = document.getElementById ("checkclass");
if (checktype==1)
objDiv.style.display = "block";
else
objDiv.style.display = "none";
}

</script>
<body>
<table border=0>
<tr>
<TD class=tablebody1>
<INPUT type=radio checked name=userclass value=0 onclick="showclasscheck(0)">隐藏　
　<INPUT type=radio name=userclass value=1 onclick="showclasscheck(1)" checked>显示</TD>
</TR>
</tr>
</table>
<div id="checkclass" align=center>测试区域</div>
</body>
posted on 2008-02-03 11:12  cqsar  阅读(409)  评论(0)    收藏  举报