1002 A+B for Polynomials (25分)
This time, you are supposed to find A+B where A and B are two polynomials.
Input Specification:
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:
K N1 aN1 N2 aN2 ... NK aNK
where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1,2,⋯,K) are the exponents and coefficients, respectively. It is given that 1≤K≤10,0≤NK<⋯<N2<N1≤1000.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input:
2 1 2.4 0 3.2 2 2 1.5 1 0.5
Sample Output:
3 2 1.5 1 2.9 0 3.2
#include<bits/stdc++.h> using namespace std; int main(){ int n,m; int exponent,count=0; double coefficient; double sum[1005]={0}; cin>>n; while(n--){ cin>>exponent>>coefficient; sum[exponent]+=coefficient; } cin>>m; while(m--){ cin>>exponent>>coefficient; sum[exponent]+=coefficient; } for(int i=1000;i>=0;--i){ if(sum[i]!=0) ++count; } cout<<count; for(int i=1000;i>=0;--i){ if (sum[i]!=0){ cout<<" "<<i<<" "; printf("%.1lf",sum[i]); } } }
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