1002 A+B for Polynomials (25分)

This time, you are supposed to find A+B where A and B are two polynomials.

Input Specification:

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial:

N1 aN1 N2 aN2 ... NK aNK

where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1,2,,K) are the exponents and coefficients, respectively. It is given that 1K10,0NK<<N2<N11000.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input:

2 1 2.4 0 3.2
2 2 1.5 1 0.5

 

Sample Output:

3 2 1.5 1 2.9 0 3.2

 

#include<bits/stdc++.h>
using namespace std;
int main(){
    int n,m;
    int exponent,count=0;
    double coefficient;
    double sum[1005]={0};
    cin>>n;
    while(n--){
        cin>>exponent>>coefficient;
        sum[exponent]+=coefficient;
    }
    cin>>m;
    while(m--){
        cin>>exponent>>coefficient;
        sum[exponent]+=coefficient;
    }
    for(int i=1000;i>=0;--i){
        if(sum[i]!=0)
            ++count;
    }
    cout<<count;
    for(int i=1000;i>=0;--i){
        if (sum[i]!=0){
            cout<<" "<<i<<" ";
            printf("%.1lf",sum[i]);
        }
    }
}

 

posted on 2022-07-24 22:01  Coder何  阅读(36)  评论(0)    收藏  举报