Word Break

Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

For example, given
s = "leetcode",
dict = ["leet", "code"].

Return true because "leetcode" can be segmented as "leet code".

class Solution {
public:
    bool wordBreak(string s, unordered_set<string> &dict) {
        int n = s.length();
        vector<bool> dp(n + 1, false);
        dp[0] = true;
        for(int i = 1; i <= n; i++){
            for(int j = 0; j < i; j++){
                if(dp[j]==true && dict.find(s.substr(j, i-j)) != dict.end()){
                    dp[i] = true;
                    break;
                }
            }
        }
        return dp[n];
    }
};

 

posted on 2014-12-03 11:59  code#swan  阅读(104)  评论(0)    收藏  举报

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