Intersection of Two Linked Lists
Write a program to find the node at which the intersection of two singly linked lists begins.
For example, the following two linked lists:
A: a1 → a2
↘
c1 → c2 → c3
↗
B: b1 → b2 → b3
begin to intersect at node c1.
Notes:
- If the two linked lists have no intersection at all, return
null. - The linked lists must retain their original structure after the function returns.
- You may assume there are no cycles anywhere in the entire linked structure.
- Your code should preferably run in O(n) time and use only O(1) memory.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *getIntersectionNode(ListNode *headA, ListNode *headB) { ListNode *p1 = headA; ListNode *p2 = headB; if (p1 == NULL || p2 == NULL) return NULL; while (p1 != NULL && p2 != NULL && p1 != p2) { p1 = p1->next; p2 = p2->next; if (p1 == p2) return p1; if (p1 == NULL) p1 = headB; if (p2 == NULL) p2 = headA; } return p1; } };
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