shell 输出文件内容

cat $filepath | while read line; do echo $line ; done
#!/bin/bash

#filepath=/opt/jenkins_home/workspace/dev-demo-haha/target/classes/application.yml
filepath=$1
if [ -f $filepath ]; then
    echo -e "\n\n\n"
    echo "================= print file $filepath start ===================="
    cat $filepath | while read line; do echo $line ; done
    echo "================= print file $filepath end ===================="
    echo -e "\n\n\n"
else
    echo "================>$filepath is not found, print file faild"
fi

 

posted @ 2017-09-29 11:38  旋转的梦  阅读(3126)  评论(0)    收藏  举报