leetcode-----87. 扰乱字符串

代码

class Solution {
public:
    bool isScramble(string s1, string s2) {
        if (s1 == s2) return true;
        string bs1 = s1, bs2 = s2;
        sort(bs1.begin(), bs1.end());
        sort(bs2.begin(), bs2.end());
        if (bs1 != bs2) return false;

        int n = s1.size();
        for (int i = 1; i <= n - 1; ++i) {
            if (isScramble(s1.substr(0, i), s2.substr(0, i)) && isScramble(s1.substr(i), s2.substr(i))) return true;
            if (isScramble(s1.substr(0, i), s2.substr(n - i)) && isScramble(s1.substr(i), s2.substr(0, n - i))) return true;
        }
        return false;
    }
};
posted @ 2020-07-15 16:37  景云ⁿ  阅读(45)  评论(0编辑  收藏  举报