django传统中间件（认证+权限）【示例】

from django.utils.deprecation import MiddlewareMixin
from django.shortcuts import redirect, HttpResponse
from django.urls import reverse
from www import models


class AuthMiddleware(MiddlewareMixin):
    def process_request(self, request):
        if request.path_info in [reverse("login")]:
            return

        # {id:'',username:"",is_super:True}
        user_dict = request.session.get("user_session_key")
        if not user_dict:
            return redirect("login")

        request.user_dict = user_dict


class PermissionMiddleware(MiddlewareMixin):

    def process_view(self, request, callback, *args, **kwargs):
        if request.path_info in [reverse("login")]:
            return

        # *超级用户校验
        if request.user_dict['is_super']:
            # 所有菜单都应该展示出来
            menus = models.Menu.objects.all().values("id", "title", "permissions__name", "permissions__code")
            request.menu_list = menus
            return

        # *普通用户校验
        # print("中间件", request.user_dict)
        # 1.获取当前访问的路由
        url_name = request.resolver_match.url_name
        # view_name = request.resolver_match.view_name  api: url_name

        # 2.获取当前用户
        user_object = models.User.objects.filter(id=request.user_dict['id']).first()
        # 获取当用户的所有菜单
        menus = models.Menu.objects.filter(user=user_object).values("id", "title", "permissions__name","permissions__code")
        request.menu_list = menus

        # 当前用户所有的权限
        # role_per_list = user_object.roles.all().values("permissions__name", "permissions__code").distinct()
        role_per_list = user_object.roles.all().values("permissions__name", "permissions__code")
        permission_dict = {item['permissions__code']: item['permissions__name'] for item in role_per_list}
        request.permission_dict = permission_dict
        print("中间件", permission_dict)
        if url_name in permission_dict:
            return

        return HttpResponse("无权访问")