递归求和:2+4+6+8+...+100任给一个数,求1到次数的和
package zxd.work622;
public class Text1 {
public static void main(String[] args) {
/*
* 递归求和:2+4+6+8+...+100任给一个数,求1到次数的和
*/
System.out.println(sum(0));
}
public static int sum(int m){
if (m==100) {
return 100;
}
return sum(m+2)+m;
}
}