LeetCode232 Implement Queue using Stacks Java 题解

题目:

Implement the following operations of a queue using stacks.

  • push(x) -- Push element x to the back of queue.
  • pop() -- Removes the element from in front of queue.
  • peek() -- Get the front element.
  • empty() -- Return whether the queue is empty.
Notes:
  • You must use only standard operations of a stack -- which means only push to toppeek/pop from topsize, and is emptyoperations are valid.
  • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
  • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

解题:

用栈实现队列,这个比用队列实现栈要麻烦一些,这里用到两个栈,两种思路。第一种就是在进栈的时候,把栈逆序放在另外一个栈,出的时候直接出另外一个栈就能够了。另外一种思路。进栈的时候不做不论什么处理。出栈的时候把栈逆序放在另外一个栈。出另外一个栈。以下就是两种的代码实现。

在进栈的时候进行处理:

class MyQueue {
    // Push element x to the back of queue.
	Stack<Integer> stack=new Stack<>();
	Stack<Integer> stack2=new Stack<>();
	
    public void push(int x) {
    	while(!stack.isEmpty())
    	{
    		stack2.push(stack.pop());
    	}
    	stack2.push(x);
    	while(!stack2.isEmpty())
    	{
    		stack.push(stack2.pop());
    	}
        
    }

    // Removes the element from in front of queue.
    public void pop() {
        stack.pop();
    }

    // Get the front element.
    public int peek() {
        return stack.peek();
    }

    // Return whether the queue is empty.
    public boolean empty() {
        return stack.isEmpty();
    }
}
在出栈的时候进行处理:

class MyQueue2 {
    // Push element x to the back of queue.
	Stack<Integer> stack=new Stack<>();
	Stack<Integer> stack2=new Stack<>();
	
    public void push(int x) {
    	while(!stack2.isEmpty())
    		stack.push(stack2.pop());
    	stack.push(x);
        
    }

    // Removes the element from in front of queue.
    public void pop() {
    	
    	while(!stack.isEmpty())
    		stack2.push(stack.pop());
        stack2.pop();
      
    }

    // Get the front element.
    public int peek() {
    	while(!stack.isEmpty())
    		stack2.push(stack.pop());
        return stack2.peek();
      
    }

    // Return whether the queue is empty.
    public boolean empty() {
    	while(!stack2.isEmpty())
    		stack.push(stack2.pop());
        return stack.isEmpty();
    }
}



posted @ 2017-07-13 11:11  claireyuancy  阅读(137)  评论(0编辑  收藏  举报