实验6

实验任务4

#include <stdio.h>
#define N 10

typedef struct {
    char isbn[20];          // isbn号
    char name[80];          // 书名
    char author[80];        // 作者
    double sales_price;     // 售价
    int  sales_count;       // 销售册数
} Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
     Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                  {"978-7-308-17047-5", "自由与爱之地:入以色列记", "云也退", 49 , 30},
                  {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                  {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 
                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                  {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
    
    printf("图书销量排名(按销售册数): \n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
    
    return 0;
}
void output(Book x[],int n){
    int i;
    for(i = 0;i < n;i++){
        printf("%-20s %-30s %-20s %-6.2f %-4d\n",
            x[i].isbn,x[i].name,
            x[i].author,x[i].sales_price,
            x[i].sales_count);
    }
}
void sort(Book x[],int n){
    int i,j;
    Book temp;
    for(i = 0;i < n - 1;i++){
        for(j = 0;j < n - 1 - i;j++)
        {
            if (x[j].sales_count < x[j+1].sales_count){
                temp = x[j];
                x[j] = x[j+1];
                x[j+1] = temp;
            }
        }
    }
}
double sales_amount(Book x[],int n){
    double sum = 0.0;
    int i;
    for (i = 0; i < n;i++){
        sum += x[i].sales_price * x[i].sales_count;
    }
    return sum;
}

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 实验5

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>

typedef struct {
    int year;
    int month;
    int day;
} Date;

void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);

void test1() {
    Date d;
    int i;
    printf("输入日期:(以形如2025-12-19这样的形式输入)\n");
    for (i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n",
            d.year, d.month, d.day, day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i, ans;
    printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n");
    for (i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);
        if (ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if (ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main() {
    printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
    return 0;
}

void input(Date *pd) {
    scanf("%d-%d-%d", &pd->year, &pd->month, &pd->day);
}

int isLeap(int y) {
    if ((y % 4 == 0 && y % 100 != 0) || (y % 400 == 0))
        return 1;
    return 0;
}

int day_of_year(Date d) {
    int days[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
    int sum = 0, i;
    if (isLeap(d.year))
        days[2] = 29;

    for (i = 1; i < d.month; i++) {
        sum += days[i];
    }
    sum += d.day;
    return sum;
}

int compare_dates(Date d1, Date d2) {
    if (d1.year != d2.year) {
        if (d1.year < d2.year) return -1;
        else return 1;
    }
    if (d1.month != d2.month) {
        if (d1.month < d2.month) return -1;
        else return 1;
    }
    if (d1.day != d2.day) {
        if (d1.day < d2.day) return -1;
        else return 1;
    }
    return 0;
}

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 实验6

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>

enum Role { admin, student, teacher };

typedef struct {
    char username[20];
    char password[20];
    enum Role type;
} Account;

void output(Account x[], int n);

int main()
{
    Account x[] = {
        {"A1001", "123456", student},
        {"A1002", "123abcdef", student},
        {"A1009", "xyz12121", student},
        {"X1009", "9213071x", admin},
        {"C11553", "129dfg32k", teacher},
        {"X3005", "921kfmg917", student}
    };
    int n = sizeof(x) / sizeof(Account);
    output(x, n);
    return 0;
}

void output(Account x[], int n)
{
    int i,j;
    char role[20];
    int len;
    for(i = 0; i < n; i++)
    {
        printf("%-10s",x[i].username);
        len = strlen(x[i].password);
        for(j = 0; j < len; j++)
        {
            printf("*");
        }
        switch(x[i].type)
        {
            case admin:strcpy(role,"admin");break;
            case student:strcpy(role,"student");break;
            case teacher:strcpy(role,"teacher");break;
        }
        printf("  %s\n",role);
    }
}

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实验7

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>

typedef struct {
    char name[20];
    char phone[12];
    int vip;
} Contact;

void set_vip_contact(Contact x[], int n, char name[]);
void output(Contact x[], int n);
void display(Contact x[], int n);

#define N 10

int main() {
    Contact list[N] = {
        {"刘一", "15510846604", 0},
        {"陈二", "18038747351", 0},
        {"张三", "18853253914", 0},
        {"李四", "13230584477", 0},
        {"王五", "15547571923", 0},
        {"赵六", "18856659351", 0},
        {"周七", "17705843215", 0},
        {"孙八", "15552933732", 0},
        {"吴九", "18077702405", 0},
        {"郑十", "18820725036", 0}
    };

    int vip_cnt, i;
    char name[20];

    printf("显示原始通讯录信息: \n");
    output(list, N);

    printf("\n输入要设置的紧急联系人个数: ");
    scanf("%d", &vip_cnt);
    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for (i = 0; i < vip_cnt; ++i) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }

    printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
    display(list, N);

    return 0;
}

void set_vip_contact(Contact x[], int n, char name[]) {
    int i;
    for (i = 0; i < n; i++) {
        if (strcmp(x[i].name, name) == 0) {
            x[i].vip = 1;
            break;
        }
    }
}

void output(Contact x[], int n) {
    int i;
    for (i = 0; i < n; ++i) {
        printf("%-10s %-15s", x[i].name, x[i].phone);
        if (x[i].vip)
            printf("  *");
        printf("\n");
    }
}

void sortContact(Contact arr[], int n) {
    int i, j;
    Contact temp;
    for (i = 0; i < n - 1; i++) {
        for (j = 0; j < n - 1 - i; j++) {
            if (arr[j].vip < arr[j + 1].vip) {
                temp = arr[j];
                arr[j] = arr[j + 1];
                arr[j + 1] = temp;
            }
            else if (arr[j].vip == arr[j + 1].vip) {
                if (strcmp(arr[j].name, arr[j + 1].name) > 0) {
                    temp = arr[j];
                    arr[j] = arr[j + 1];
                    arr[j + 1] = temp;
                }
            }
        }
    }
}

void display(Contact x[], int n) {
    Contact temp[N];
    int i;
    for (i = 0; i < n; i++) {
        temp[i] = x[i];
    }
    sortContact(temp, n);
    output(temp, n);
}

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posted @ 2026-06-16 15:02  刺客伍六柒(上学ing)  阅读(7)  评论(0)    收藏  举报