实验四的作业
task 1-1:
#include<stdio.h> #defineN4 intmain() { inta[N]={2,0,2,2}; charb[N]={'2','0','2','2'}; inti; printf("sizeof(int)=%d\n",sizeof(int)); printf("sizeof(char)=%d\n",sizeof(char)); printf("\n"); //输出数组a中每个元素的地址、值 for(i=0;i<N;++i) printf("%p:%d\n",&a[i],a[i]); printf("\n"); //输出数组b中每个元素的地址、值 for(i=0;i<N;++i) printf("%p:%c\n",&b[i],b[i]); printf("\n"); //输出数组名a和b对应的值 printf("a=%p\n",a); printf("b=%p\n",b); return0; } 连续 4连续 1不一样
task 1-2:
#include<stdio.h> #define N 2 #define M 3 int main() { int a[N][M] = { {1,2,3},{4,5,6} }; char b[N][M] = { {'1','2','3'},{'4','5','6'} }; int i, j; for (i = 0; i < N; ++i) for (j = 0; j < M; ++j) printf("%p: %d\n", &a[i][j], a[i][j]); printf("\n"); for (i = 0; i < N; ++i) for (j = 0; j < M; ++j) printf("%p: %c\n", &b[i][j], b[i][j]); return 0; } //问题一:是;每个元素占4个 //问题二:是;每个元素占1个
task 2:
#define _CRT_SECURE_NO_WARNINGS #include<stdio.h> int days_of_year(int year, int month, int day); int main() { int year, month, day; int days; while (scanf("%d%d%d", &year, &month, &day) !=EOF) { days = days_of_year(year, month, day); printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days); } return 0; } int days_of_year(int year, int month, int day) { int yuefen[13], i,j,s=0; for (i = 1; i < 13; i++) { if (i == 2) { if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) yuefen[i] = 29; else yuefen[i] = 28; } if (i == 1 || i == 3 || i == 5 || i == 7 || i == 8 || i == 10 || i == 12) yuefen[i] = 31; if (i == 4 || i == 6 || i == 9 || i == 11) yuefen[i] = 30; } for (j = 1; j < month; j++) { s = s + yuefen[j]; } s = s + day; return s; }
task 3:
//task.3// #include<stdio.h> #define N 5 //函数声明 void input(int x[],int n); void output(int x[],int n); double average(int x[],int n); void sort(int x[],int n); int main() { int scores[N]; double ave; printf("录入%d个分数:\n",N); input(scores,N); printf("\n输出课程分数:\n"); output(scores,N); printf("\n课程分数处理:计算均分、排序...\n"); ave = average(scores,N); sort(scores,N); printf("\n输出课程平均分:%.2f\n",ave); printf("\n输出课程分数(高->低):\n"); output(scores,N); return 0; } //函数定义 //输入n个整数保存到整型数组x中 void input(int x[],int n) { int i; for(i=0;i<n;++i) scanf("%d",&x[i]); } //输出整型数组x中n个元素 void output(int x[],int n) { int i; for(i=0;i<n;++i) printf("%d ",x[i]); printf("\n"); } double average(int x[],int n) { int i; double s=0,average; for(i=0;i<n;++i) { s+=x[i]; } average=s/n; return average; } void sort(int x[],int n) { int i,j,t; for(i=0;i<n-1;++i) { for(j=0;j<n-i-1;++j) if(x[j]<x[j+1]) { t=x[j]; x[j]=x[j+1]; x[j+1]=t; } } }
task 4:
//task.4.c// #include<stdio.h> void dec2n(int x,int n); int main() { int x; printf("输入一个十进制整数; "); scanf("%d",&x); dec2n(x,2); dec2n(x,8); dec2n(x,16); return 0; } void dec2n(int x,int n) { int i=0,j,a[100]; char b[100]; if(n==16) { for(i=0;x!=0;i++,j++) { if(x%16==10) b[i]='A'; else if(x%16==11) b[i]='B'; else if(x%16==12) b[i]='C'; else if(x%16==13) b[i]='D'; else if(x%16==14) b[i]='E'; else if(x%16==15) b[i]='F'; else b[i]=x%16+'0'; x=x/16; } for(j=i-1;j>=0;j--) printf("%c",b[j]); printf("\n"); } else { do{ a[i] = x%n; x =x/n; i++; j++; }while(x!=0); for(j=i-1;j>=0;j--) printf("%d",a[j]); printf("\n"); } }
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task 5:
//task.5// #include<stdio.h> int main() { int n,i,j; printf("Enter n:"); while (scanf("%d",&n)!=EOF) { int a[n][n]; for(i=0;i<n;i++) { for(j=i;j<n;j++) {a[i][j]=i+1;} } for(j=0;j<n;j++) { for(i=j;i<n;i++) {a[i][j]=j+1;} } for(i=0;i<n;i++) { for(j=0;j<n;j++) { printf("%d ",a[i][j]); } printf("\n"); } printf("\n\nEnter n:"); } return 0; }
task 6:
//task.6// #include<stdio.h> #define N 80 int main() { char views1[N]="hey,c,i hate u."; char views2[N]="hey,c,i love u."; int i,j; char t; printf("original views:\n"); printf("views1:\n"); for(j=0;j<N;j++) printf("%c",views1[j]); printf("\n"); printf("views2:\n"); for(j=0;j<N;j++) printf("%c",views2[j]); printf("\n"); printf("swapping...\n"); for(i=0;i<N;i++) { t=views1[i]; views1[i]=views2[i]; views2[i]=t; } printf("views1:"); for(j=0;j<N;j++) printf("%c",views1[j]); printf("\n"); printf("views2:"); for(j=0;j<N;j++) printf("%c",views2[j]); }
task 7:
//task.7// #include<stdio.h> #include<string.h> #define N 5 #define M 20 void bubble_sort(char str[][M],int n); int main() { char name[][M] = {"Bob","Bill","Joseph","Taylor","George"}; int i; printf("输出初始名单:\n"); for(i=0;i<N;i++) printf("%s\n",name[i]); printf("\n排序中...\n"); bubble_sort(name,N); printf("\n按字典输出名单:\n"); for(i=0;i<N;i++) printf("%s\n",name[i]); return 0; } void bubble_sort(char str[][M],int n) { int i,j; char temp[M]; for(i=0;i<n-1;i++) { for(j=i+1;j<n;j++) if(strcmp(str[j],str[i])<0) { strcpy(temp,str[i]); strcpy(str[i],str[j]); strcpy(str[j],temp); } } }









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