java基础知识细节遗漏补丁

`


INSERT INTO users (name, email, age)
VALUES (#{name}, #{email}, #{age})

<!-- 更新语句 -->
<update id="updateUser" parameterType="com.example.model.User">
    UPDATE users
    SET name = #{name}, email = #{email}, age = #{age}
    WHERE id = #{id}
</update>

<!-- 查询语句 -->
<select id="selectUserById" parameterType="int" resultType="com.example.model.User">
    SELECT id, name, email, age
    FROM users
    WHERE id = #{id}
</select>

`

posted @ 2025-07-04 11:26  ruo_feng  阅读(10)  评论(0)    收藏  举报
-->