JS - 获取 url 参数

function getUrlParam(name) { var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)"); var r = decodeURI(window.location.search.substr(1)).match(reg); if (r != null) { return unescape(r[2]); }else{ return null; } } 若转载请注明出处: http://xiaowiba.com/archives/1010/