[LeetCode&Python] Problem 766. Toeplitz Matrix
A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.
Now given an M x N
matrix, return True
if and only if the matrix is Toeplitz.
Example 1:
Input: matrix = [ [1,2,3,4], [5,1,2,3], [9,5,1,2] ] Output: True Explanation: In the above grid, the diagonals are: "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]". In each diagonal all elements are the same, so the answer is True.
Example 2:
Input: matrix = [ [1,2], [2,2] ] Output: False Explanation: The diagonal "[1, 2]" has different elements.
Note:
matrix
will be a 2D array of integers.matrix
will have a number of rows and columns in range[1, 20]
.matrix[i][j]
will be integers in range[0, 99]
.
class Solution: def isToeplitzMatrix(self, matrix): """ :type matrix: List[List[int]] :rtype: bool """ Flag=True m=len(matrix) n=len(matrix[0]) for i in range(m): row=i column=0 stan=matrix[i][0] while row<m and column<n: if matrix[row][column]!=stan: Flag=False break row+=1 column+=1 if Flag: for j in range(1,n): column=j row=0 stan=matrix[0][j] while column<n and row<m: if matrix[row][column]!=stan: Flag=False break row+=1 column+=1 return Flag