[LeetCode&Python] Problem 387. First Unique Character in a String
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.
Examples:
s = "leetcode" return 0. s = "loveleetcode", return 2.
Note: You may assume the string contain only lowercase letters.
from collections import Counter class Solution(object): def firstUniqChar(self, s): """ :type s: str :rtype: int """ m=100000 a=Counter(s) for i in a: if a[i]==1: ind=s.index(i) if m>ind: m=ind if m<100000: return m return -1