语法:TRUNC(date[,fmt])
TRUNC(number[,decimals])
Select trunc(TO_DATE('24-11-1999 08:00 pm','dd-mm-yyyy hh:mi am')) RESULT From dual
= 11/24/1999
select trunc(sysdate,'day') result from dual
=本周第一天
select trunc(sysdate,'yy') result from dual
=本年第一天
select trunc(sysdate,'yy')-1 result from dual
=上年最后一天
select trunc(sysdate,'mm') result from dual
=本月第一天
select trunc(sysdate,'dd') result from dual
当天
Select trunc(2999.99222,-3) From dual = 2000
Select trunc(2999.99222,1) From dual =2999.9
Select trunc(2999.99222,2) From dual = 2999.99
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